1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vampirchik [111]
3 years ago
7

Johanna makes the table below to organize her notes about centripetal forces. Which type of force should she place in the cell m

arked X?

Chemistry
2 answers:
grin007 [14]3 years ago
8 0
X: radius,
Y: tangental speed. 
Valentin [98]3 years ago
3 0

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

Centripetal force is defined as the force that acts on a body moving in a circular path and is directed towards the center around which the body is moving.

Mathematically,

F_c=\frac{mv^2}{r}

Where,

F_c = centripetal force

m = mass of the object

v = tangential velocity

r = radius of the path

From the above relation, X corresponds to the radius and Y corresponds to the tangential velocity.

Hence, the correct answer is option C.

You might be interested in
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 42. g of butane is m
taurus [48]

Answer:

127 grams of carbon dioxide

Explanation:

We need to determine the chemical equation first. Butane has a chemical formula of C_4H_{10}, oxygen is O_2, carbon dioxide is CO_2, and water is H_2O. The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:

C_4H_{10}+O_2 ⇒ CO_2+H_2O

But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:

C_4H_{10}+O_2 ⇒ 4CO_2+5H_2O

However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:

C_4H_{10}+6.5O_2 ⇒ 4CO_2+5H_2O

Finally, multiply everything by 2 to get whole number coefficients:

2C_4H_{10}+13O_2 ⇒ 8CO_2+10H_2O

Ah, now we can actually get to the problem!

We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.

The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:

42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2

150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2

Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.

Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:

2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2

Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.

<em>~ an aesthetics lover</em>

4 0
3 years ago
In a certain experiment, 28.0 mL of 0.250 M HNO3and 53.0 mL of 0.320 M KOH are mixed. Calculate the number of moles of water for
Xelga [282]

Answer:

The number of moles of water formed in the resulting reaction is 6.03

[H+]: 37,2 M

[OH-]: 37,2 M

Explanation:

HNO3  +  KOH ----> KNO3 + H2O

First, we must discover the limiting reagent and we need to find out the moles, we use for this.

Moles that are used = Molarity / volume

HNO3 : 0,250 mol/L / 0,028L = 8,93 moles

KOH : 0,320 mol/L / 0,053L = 6,03 moles

The ratio of the reagents by stoichiometry is 1 to 1, so the limiting reagent is KOH, if I need 1 mole of nitric per mole of KOH, for every 8.93 moles I will need the same. However I have only 6.03 moles of KOH

The ratio of the reagents/products by stoichiometry is 1 to 1 so if I need 1 mol of KOH to make 1 mol of Water, 6,03 moles of KOH are used to make 6,03 moles of H2O.

The equilibrium of water is this:

2H2O ⇄ H3O+  +  OH-

2 moles of water are broken down into 1 mole of hydronium (H3O +) and 1 mole of hydroxyl (OH-)

6,03 moles of water are broken down into the half of those moles, so we have 3,015 moles of H3O+ and 3,015 moles of OH- but these moles are in 81,0 mL (the volume of the two solutions, 28 mL + 53 mL)

We must find out the moles in 1000 mL (1 L) so let's apply the rule of three.

81 mL ____ 3,015 moles

1000 mL ___ ( 1000 . 3,015) /81 = 37,2 M

7 0
3 years ago
One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
The balanced chemical equation is written as:

<span>CsF(s) + XeF6(s) ------> CsXeF7(s)

We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride.  We calculate as follows:

11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
6 0
3 years ago
Read 2 more answers
How do chemists solve problems?
Westkost [7]

Answer:Chemistry problems can be solved using a variety of techniques.

Explanation:  Many chemistry teachers and most introductory chemistry texts illustrate problem solutions using the factor-label method. ... The use of analogies and schematic diagrams results in higher achievement on problems involving moles, stoichiometry, and molarity. Hope this helped!

4 0
3 years ago
Indica las condiciones que debe cumplir una colisión entre moléculas para que se produzca una reacción química
g100num [7]

Answer:

Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.

6 0
3 years ago
Other questions:
  • How many moles of water are In 44.99 grams
    12·1 answer
  • How is the structure of a hammer related to its function
    15·1 answer
  • Which of the following has the shortest wavelength?
    9·2 answers
  • The Human Excretory System
    13·2 answers
  • Which type of stress causes rocks to fold?
    15·2 answers
  • Why is the separation of waste rock before mining so important?​
    7·1 answer
  • What is the mass number of sodium?
    5·2 answers
  • Which substance combines with iron in the presence of water to form rust?
    12·2 answers
  • A 7.45 L container holds a mixture of two gases at 15 °C. The partial pressures of gas A and gas B, respectively, are 0.364 atm
    5·1 answer
  • How many grams of potassium chloride (KCI) are needed to prepare 0.750 L of a 1.50 M solution of potassium chloride in water?​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!