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stiks02 [169]
2 years ago
6

Define a salt bridge. Question 6 options: A pathway between the cathode and anode in which ions are oxidized. A pathway by which

counterions can flow between the half-cells without the solutions in the half-cell totally mixing. A pathway in which no ions flow. A pathway between the cathode and anode in which ions are reduced. A pathway, composed of salt water, that ions pass through.
Chemistry
1 answer:
Stells [14]2 years ago
3 0

Answer:

A pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

Explanation:

In a voltaic cell, oxidation occurs at the anode and reduction occurs at the cathode.

Hence, there is a build up of positive ions at the anode and a build up of negative ions at the cathode. This tends to disrupt the electrical neutrality of the half cells.

Hence, there is a need for negative ions in the salt bridge to flow towards the anode and positive ions in the salt bridge to flow towards the cathode in order to maintain the electrical neutrality of the cells.

Hence, a salt bridge provides a pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

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A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has
natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

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2 years ago
Why does temperature change always move from regions of hot to regions of cold?
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Answer:

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2. When heated above 500 ºC, potassium nitrate decomposes according to the equation below. 4KNO3 2K2O + 2N2 + 5O2A.If oxygen is
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Answer:

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The rate of formation of N2 is also 0.12 M/s

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Explanation:

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Rate of formation of O2 is 0.3 M/s

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Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

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