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stiks02 [169]
3 years ago
6

Define a salt bridge. Question 6 options: A pathway between the cathode and anode in which ions are oxidized. A pathway by which

counterions can flow between the half-cells without the solutions in the half-cell totally mixing. A pathway in which no ions flow. A pathway between the cathode and anode in which ions are reduced. A pathway, composed of salt water, that ions pass through.
Chemistry
1 answer:
Stells [14]3 years ago
3 0

Answer:

A pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

Explanation:

In a voltaic cell, oxidation occurs at the anode and reduction occurs at the cathode.

Hence, there is a build up of positive ions at the anode and a build up of negative ions at the cathode. This tends to disrupt the electrical neutrality of the half cells.

Hence, there is a need for negative ions in the salt bridge to flow towards the anode and positive ions in the salt bridge to flow towards the cathode in order to maintain the electrical neutrality of the cells.

Hence, a salt bridge provides a pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

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3 years ago
Read 2 more answers
How many total atoms are in 0.670 g of p2o5?
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The molecular formula for compound is  P_{2}O_{5} mass of compound is 0.670 g.

To calculate number of atoms first calculate number of moles in the compound as follows:

n=\frac{m}{M}

Molar mass of  P_{2}O_{5} is 283.886 g/mol, thus,

n=\frac{0.670 g}{283.886 g/mol}=0.00236 mol

Thus, number of mole of P_{2}O_{5} is 0.00236 mol.

From the molecular formula 1 mole of P_{2}O_{5} has 2 mol of P (phosphorus) and 5 mol of O (oxygen).

Thus, number of moles of P and O in 0.00236 mol of P_{2}O_{5} will be:

n_{P}=2\times 0.00236 mol=0.00472 mol

Similarly,

n_{O}=5\times 0.00236 mol=0.0118 mol

Now, in 1 mol of an element there are 6.023\times 10^{23} atoms.

Number of atoms of P will be:

N_{P}=0.00472\times 6.023\times 10^{23}=2.84\times 10^{21}atoms

Similarly, number of atoms of O will be:

N_{O}=0.0118\times 6.023\times 10^{23}=7.11\times 10^{21}atoms

Total number of atoms will be sum of number of atoms of P and O:

N_{Total}=N_{P}+N_{O}=2.84\times 10^{21}+7.11\times 10^{21}=9.95\times 10^{21} atoms

Therefore, total number of atoms in P_{2}O_{5} will be 9.95\times 10^{21} atoms.

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