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stiks02 [169]
2 years ago
6

Define a salt bridge. Question 6 options: A pathway between the cathode and anode in which ions are oxidized. A pathway by which

counterions can flow between the half-cells without the solutions in the half-cell totally mixing. A pathway in which no ions flow. A pathway between the cathode and anode in which ions are reduced. A pathway, composed of salt water, that ions pass through.
Chemistry
1 answer:
Stells [14]2 years ago
3 0

Answer:

A pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

Explanation:

In a voltaic cell, oxidation occurs at the anode and reduction occurs at the cathode.

Hence, there is a build up of positive ions at the anode and a build up of negative ions at the cathode. This tends to disrupt the electrical neutrality of the half cells.

Hence, there is a need for negative ions in the salt bridge to flow towards the anode and positive ions in the salt bridge to flow towards the cathode in order to maintain the electrical neutrality of the cells.

Hence, a salt bridge provides a pathway by which counterions can flow between the half-cells without the solutions in the half-cell totally mixing.

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If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
GaryK [48]
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
And the total number of snow flakes per minute on the entire lawn is:
   
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
       
In one hour (or 60 minutes) we get a total of:
   
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
       
The total mass of which would be:
   
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
       
So 54.432 kg of snow accumulates every hour on the lawn.</span>
7 0
3 years ago
Who developed the orbital model of the atom?
Nataliya [291]

Answer:

Ernest Rutherford

Explanation:

that's I think

7 0
3 years ago
Question 6 of 10
Marta_Voda [28]

Answer:

B. A chemist

<em>Hope it's help :)</em>

5 0
3 years ago
What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent
dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, \text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0
3 years ago
Fulgurites are the products of the melting that occurs when lightning strikes the earth. Microscopic examination of a sand fulgu
BlackZzzverrR [31]

Answer:

Fe₃Si₇

Explanation:

In order to determine the empirical formula, we have to follow a series of steps.

Step 1: Determine the percent composition

Fe: 46.01%

Si: 53.99%

Step 2: Divide each percentage by the atomic mass of the element

Fe: 46.01/55.85 = 0.8238

Si: 53.99/28.09 = 1.922

Step 3: Divide all the numbers by the smallest one

Fe: 0.8238/0.8238 = 1

Si: 1.922/0.8238 = 2.33

Step 4: Multiply by numbers that make the coefficients whole.

Fe: 1 × 3 = 3

Si: 2.33 × 3 = 7

The empirical formula is Fe₃Si₇.

5 0
3 years ago
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