You run from your friends house that is 1k away. You then walk home. What distance did you travel?
1 answer:
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Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
Answer:
135°.
Explanation:
R = 75 ohm, L = 0.01 H, C = 4 micro F = 4 x 10^-6 F
Frequency is equal to the half of resonant frequency.
Let f0 be the resonant frequency.
f0 = 796.2 Hz
f = f0 / 2 = 398.1 Hz
So, XL = 2 x 3.14 x f x L = 2 x 3.14 x 398.1 x 0.01 = 25 ohm
Xc = 100 ohm
tan Ф = (25 - 100) / 75 = - 1
Ф = 135°
Thus, the phase difference is 135°.