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Xelga [282]
2 years ago
8

A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's

Physics
1 answer:
9966 [12]2 years ago
6 0

By the law of universal gravitation, the gravitational force <em>F</em> between the satellite (mass <em>m</em>) and planet (mass <em>M</em>) is

<em>F</em> = <em>G</em> <em>M</em> <em>m</em> / <em>R </em>²

where

<em>• G</em> = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant

• <em>R</em> = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet

Solve for <em>M</em> :

<em>M</em> = <em>F R</em> ² / (<em>G</em> <em>m</em>)

<em>M</em> = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (<em>G</em> (6 × 10³ kg))

<em>M</em> ≈ 2.8 × 10¹⁴ kg

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3 years ago
What are groups 1,2 and 3 examples of on the periodic table
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3 years ago
What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical posi
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 ΔU = 2 mg h

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the potential energy at the highest point is

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the potential energy at the lowest point is

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Answer:

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