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Monica [59]
4 years ago
6

A 5.0-gram sample of Fe(s) is to be placed in 100. milliliters of HCl(aq). Which changes will result in the fastest rate of reac

tion? 1. increasing the surface area of Fe(s) and increasing the concentration of HCl(aq) 2. increasing the surface area of Fe(s) and decreasing the concentration of HCl(aq) 3. decreasing the surface area of Fe(s) and increasing the concentration of HCl(aq) 4. decreasing the surface area of Fe(s) and decreasing the concentration of HCl(aq)
Chemistry
1 answer:
sveta [45]4 years ago
6 0
The answer is <span>increasing the surface area of Fe(s) and increasing the concentration of HCl(aq). 

the rate of reaction can be increased if the interaction between the reactants in better. by increasing the surface area of a solid, such as Fe, you make more possible each molecule of Fe to interact with HCl. Also, by increasing the concentration of HCl, it mean there is more molecule of HCl to interact with Fe.</span>
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Wewaii [24]

Explanation:

Number 1

Q = 4280J

mass = x

∆∅ = 34.5 - 22

∆∅ = 12.5°C

Specific heat capacity of water = 4200J

Q = mc∆∅

4280 = x(4200)(12.5)

4280 = 52500x

x = 4280/52500

x = 0.0815kg

Number 2

c = x

Q = 3750

m = 315g

∆∅ = 78 - 28.4

∆∅ = 49.6°C

Q = mc∆∅

3750 = 315×x×49.6

3750 = 15624x

x = 3750/15624

x = 0.2400J(g°C)-¹

Number 3

c = 0.448

Q = 35000

m = 454g

∆∅ = x

Q = mc∆∅

35000 = 454(0.448)(x)

35000 = 203.392x

x = 35000/203.392

x = 172.0815

∅2 - ∅1 = ∆∅

∅2 = ∆∅ + ∅1

∅2 = 172.0815 + 24

∅2 = 196.0815

∅2 = 196°C

Number 4

Q = 8750J

m = 75g = 0.075

c = 4200J/kg/°C

∆∅ = x

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8750 = 0.075(4200)∆∅

8750 = 315×x

x = 8750/315

x = 27.7778

∅2 - ∅1 = 27.7778

∅2 = 27.7778 + ∅1

∅2 = 27.7778 + 23

∅2 = 50.7778

∅2 = 50.8°C

Number 5

Q = 38800J

c = 0.448J/(g°C)

∆∅ = 178 - 24.5

∆∅ = 153.5°C

m = x

Q = mc∆∅

38800 = x × 0.448 × 153.5

38800 = 68.768x

x = 38800/68.768

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5 0
3 years ago
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mario62 [17]

Explanation:

We have given the acid that is, acetic acid. It is known that acetic acid is a weak acid.

Therefore, formula that depicts relationship between pH, pK_{a} and weak acid is as follows.

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where,          [HA] = concentration of weak acid

      [A^{-}] = concentration of conjugate base of given weak acid

Since, we have to calculate the concentration of conjugate base of acetic acid. So, let it be equal to x. Whereas concentration of acetic acid is 10 mmol, pK_{a} is 4.74 and pH is 5.03.

Hence, putting these values in the above formula as follows.

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Thus, we can conclude that there is 19.4 mmol acetate (the conjugate base of acetic acid) will be needed to add to this given solution.

8 0
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Mamont248 [21]
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OverLord2011 [107]

Answer:

True

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timofeeve [1]
The answer should be A

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