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kondaur [170]
3 years ago
7

Which natural methods remove CO2 from the atmosphere?

Chemistry
2 answers:
FromTheMoon [43]3 years ago
5 0
I would say the answers would be 
A) respiration of living organisms.
and 
D)<span>absorption of CO2 from the atmosphere by ocean water.</span>
Gre4nikov [31]3 years ago
3 0

Answer:

A,D

Explanation:

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Both protons and neutrons (and their anti-particles) froze out:
VladimirAG [237]
I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge. 
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3 years ago
Which statement is true?
algol [13]

The statement that is true is that B. Atoms always remain intact during chemical reactions.

Atoms simply mean the <u>basic units of matter.</u> They're the defining structure of an element. Atom is also known as the smallest unit of matter.

It should be noted that atoms always remain intact during chemical reactions. They cannot be added and removed when there are <em>chemical reactions.</em>

Read related link on:

brainly.com/question/19338615

3 0
2 years ago
Read 2 more answers
Convert 675 nanograms to milligrams.
STALIN [3.7K]

675 nanograms is equivalent to 6.75 × 10-⁴ milligrams.

<h3>How to convert nanograms to milligrams?</h3>

Nanograms is a unit of mass equal to 0.000000001 grams and has a symbol of ng.

On the other hand, milligrams is another unit of mass equal to 0.001grams and has a symbol of mg.

Nanograms and milligrams are both units of mass and can be inter-convertible as follows:

1 nanogram = 1 × 10-⁶ milligram

According to this question, 675 nanograms is equivalent to 675 × 10-⁶ milligrams.

Therefore, 675 nanograms is equivalent to 6.75 × 10-⁴ milligrams.

Learn more about milligrams at: brainly.com/question/20320382

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7 0
1 year ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
Compare the density of the ocean crust and the continental crust. If they were to collide, predict which one would push under th
uysha [10]

Answer:

The difference between the density of the ocean crust and the continental crust is the fact that the ocean crust is denser than the continental crust. Meaning, the continental crust is likely to push over the oceanic crust considering it has less dense.

Explanation:

I hope this helps, the last time I learned this was in 5th grade and I am i currently in the 11th grade....

5 0
3 years ago
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