3 years ago

How do astronomers best learn about distant objects in the universe

Physics

2 answers:

3241004551 [841]3 years ago

7 0

The answer will be C based on what I had researched

Brilliant_brown [7]3 years ago

5 0

They collect and analyze data from the objects' electromagnetic radiation.

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Which of the following measurements changes based on the strength of gravity? A.Mass B.Size C.Length D.Weight

kaheart [24]

Weight. As a scientific term Weight is referred to as the force that Earth and objects have with each other. Your weight can be different on other planets.

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3 years ago

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Can the object be in motion if the net force acting on it is zero? explain.

artcher [175]

When object travels with uniform velocity, no force acts on it. hence , yes.

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A spring is hung from the ceiling. A 0.442-kg block is then attached to the free end of the spring. When released from rest, the

siniylev [52]

Answer:

$K=58.8N/m$

Explanation:

From the question we are told that:

Mass $M=0.442$

Drop distance $d=0.150$

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$K=\frac{2mg}{x}$

$K=\frac{2*0.442*9.8}{1.150}$

$K=58.8N/m$

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A man travels 15 km east before turning around and heading 5 km west. What is his displacement?

navik [9.2K]

Answer:

10 km East

Displacement is the shortest path between two points.

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What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?

Nastasia [14]

Answer:

$F=1.26*10^{-3}N$

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

$F=\frac{kq_1q_2}{d^2}$

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges( $q_1,q_2$ ) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

$F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N$

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3 years ago