Answer:
The capacitance per unit length is 
(b) is correct option.
Explanation:
Given that,
Radius a= 2.50 mm
Radius b=7.50 mm
Dielectric constant = 3.68
Potential difference = 120 V
We need to calculate charge per length for the capacitance
Using formula of charge per length
Put the value into the formula
We know that,
We need to calculate the capacitance per unit length
Using formula of capacitance per unit length
Hence, The capacitance per unit length is
Answer:
Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.
Explanation:
Lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students. Option D is correct.
<h3>
What is a Transverse wave?</h3>
- The wave in which the oscillation of particles is is perpendicular to the direction of energy transfer.
- The students can make a transverse wave by raising their hands up and then down, one student at a time.
- The raised hand represents the oscillation of particles while the sequence of the raising hand represents the direction of energy transfer.
Therefore, lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students.
Learn more about Transverse waves:
brainly.com/question/3813804
Sorry I didn't see this before...
Okay, I see two major problems with this student's experiment:
1) Nitric acid Won't Dissolve in Methane
Nitric acid is what's called a mineral acid. That means it is inorganic (it doesn't contain carbon) and dissolves in water.
Methane is an organic molecule (it contains carbon). It literally cannot dissolve nitric acid. Here's why:
For nitric acid (HNO3) to dissolve into a solvent, that solvent must be polar. It must have a charge to pull the positively charged Hydrogen off of the Oxygen. Methane has no charge, since its carbon and hydrogens have nearly perfect covalent bonds. Thus it cannot dissolve nitric acid. There will be no solution. That leads to the next problem:
2) He's Not actually Measuring a Solution
He's picking up the pH of the pure nitric acid. Since it didn't dissolve, what's left isn't a solution—it's like mixing oil and water. He has groups of methane and groups of nitric acid. Since methane is perfectly neutral (neither acid nor base), the electronic instrument is only picking up the extremely acidic nitric acid. There's no point to what he's doing.
Does that help?
