Option (i) would have the highest 2nd Ionization Energy.
Option (i) is Sodium.
Can be Written as 2, 8 , 1
For its 1st Ionization energy... It'd be extremely easy to remove that Electron cos its on the outermost shell.
Now After Removing that Electron...
Sodium's Electronic Configuration Reduces to that of Neon Which is 2, 8.
Neon has a very stable Octet.
It would take an ENORMOUS amount of energy to break its Octet stability... that is... Remove 1 electron from its Octet.
So
Option (i) [Sodium] has the highest 2nd Ionization Energy
Answer: Dinitrogen pentoxide
Explanation:
Answer:
Hey there!
That would be the alkaline earth metals.
Hope this helps :)
Answer:
pH ( potential Hydrogen ) is a negative logarithm of molar concentration of hydrogen ions.
![pH = - log[H {}^{ + } ]](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20log%5BH%20%7B%7D%5E%7B%20%2B%20%7D%20%5D)
therefore:
