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VashaNatasha [74]
3 years ago
14

Molly made 3600 ml of tea for a party, and she served the tea divided equally in 12 cups. how many liters of tea did molly put i

n each cup

Chemistry
2 answers:
ikadub [295]3 years ago
8 0

0.3 is the answer, hope this helps :)


vampirchik [111]3 years ago
5 0
I hope this helps!!! (:

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10) A student’s calculation w as found to have a 15.6% error, and the actual value w as determined to be 25.7 mL. W hat are the
goblinko [34]

Answer:

The actual value = 25.7 ml

The error = 15.6%

This means that the value of error = 0.156 * 25.7 = 4.0092 ml

Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.

This means that the two possible readings are:

either : 25.7 + 4.0092  = 29.7092 ml

or : 25.7 - 4.0092  = 21.6908 ml

Explanation:

7 0
3 years ago
At 1023 K and 1 atm, a 3.00 gram sample of Snoz(s) (gram-formula mass = 151 g/mol) reacts with hydrogen gas to produce tin and w
Blizzard [7]

Answer:

2 moles of Sn are produced when 4 moles of H2(g) are consumed completely

Explanation:

to determine the number of moles of sn (l) produced when 4.0 moles of H2 (g) is consumed completely.

First, find the number of moles of H2 consumed by taking this as limiting reagent.

                                           n = \frac{g}{M.W (g/mol)}

Then find the moles of Sn (l) taking into account the stoichiometric relationship between H2(g) and Sn(l). 2:1

                          SnO_{2} (s) + 2H_{2}(g)  ⇒  Sn(l) + 2H_{2}O(g)

                              mol Sn(l) = \frac{1mol Sn}{2mol H_{2} } . 4 mol H_{2} = 2  mol

∴2 moles of Sn are produced when 4 moles of H2(g) are consumed completely.

4 0
3 years ago
A metal forms the fluoride MF3. Electrolysis of the molten fluoride by a current of 3.86 A for 16.2 minutes deposits 1.25 g of t
larisa86 [58]

<u>Answer: </u>The molar mass of the metal is 96.45 g/mol

<u>Explanation:</u>

The fluoride of the metal formed is MF_3

The oxidation half-reaction follows:

M\rightarrow M^{3+}+3e^-

Calculating the theoretical mass deposited by using Faraday's law, which is:

m=\frac{M\times I\times t(s)}{n\times F}       ......(1)

where,

m = actual mass deposited = 1.25 g

M = molar mass of metal = ?

I = average current = 3.86 A

t = time period in seconds = 16.2 min = 972 s            (Conversion factor: 1 min = 60 sec)

n = number of electrons exchanged = 3mol^{-1}

F = Faraday's constant = 96500 C

Putting values in equation 1, we get:

1.25g=\frac{M\times 3.86A\times 972s}{3mol^{-1}\times 96500 C}\\\\M=\frac{1.25g\times 3mol^{-1}\times 96500 C}{3.86A\times 972s}\\\\M=96.45g/mol

Hence, the molar mass of the metal is 96.45 g/mol

7 0
3 years ago
What is the next step if the data from an investigation do not support the original hypothesis?
IceJOKER [234]
Change one of the variables and try again
5 0
4 years ago
“Some types of vaccines need only one shot to protect you for the rest of your life. Other types, such as the one for seasonal f
IrinaK [193]
Yearly, is the answer.
8 0
3 years ago
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