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VashaNatasha [74]
3 years ago
14

Molly made 3600 ml of tea for a party, and she served the tea divided equally in 12 cups. how many liters of tea did molly put i

n each cup

Chemistry
2 answers:
ikadub [295]3 years ago
8 0

0.3 is the answer, hope this helps :)


vampirchik [111]3 years ago
5 0
I hope this helps!!! (:

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If the oxidation number of an atom decreases, the atom has undergone oxidation.
Bumek [7]

Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.

For example,

Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.

As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.

So, answer is b.False.

8 0
3 years ago
Draw the aromatic compound toluene (methylbenzene). show all hydrogen atoms, including those on the ring.
Otrada [13]

Aromatic compound has continuous cyclic structure with( 4n+2)π electrons (Huckels rule), where n = 0,1,2…

Here number of pi electron are 6, where 4 from two double bond and 2 from nitrogen non-bonding electrons, hence it has total 6 pi electrons, therefore

6= ( 4n+2)π

4 = 4n  

n =1

 

Hence it is an aromatic compound  

 


7 0
3 years ago
A recipe for chocolate cake calls for 236.6 mL of buttermilk.
Mice21 [21]

Answer:236.6

Explanation:

5 0
2 years ago
You are given a solid that is a mixture of na2so4 and k2so4.
Murljashka [212]

Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

(Na)₂SO₄=2Na⁺ +  SO_{4}^{2-}

Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of SO_{4}^{2-} ion is present.        

5 0
3 years ago
2. A sample of apple juice has a volume of 4 mL and a mass of 72 g. What is the density
tangare [24]
  • Mass=72g
  • Volume=4mL

\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \sf\longmapsto Density=\dfrac{72}{4}

\\ \sf\longmapsto Density=18g/mL

5 0
2 years ago
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