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Aneli [31]
3 years ago
13

what mass of carbon dioxide will be produced when 12.9 g of butane reacts with an excess of oxygen in the following reaction?

Chemistry
1 answer:
Nadya [2.5K]3 years ago
3 0
39.1 gCO2
I think if that’s an option
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How does the maximum oxidation number vary across a period in the main groups? Is the pattern in Period 2 different?
snow_lady [41]

As a result, the greatest number of an atom's oxidation state will gradually rise over each period of the periodic table. For instance, the third period's highest value of the oxidation number will fall between 1 and 7.

  • The Periodic Table only consistently varies the oxidation numbers of Group 1 and Group 2 metals in their compounds, which are always +1 and +2, respectively.
  • Elements have an increasing number of valence electrons that can range from 1 to 8 and move from left to right over time. However, when H or O are added to an element first, the element's valency rises to 4, then falls to zero.
<h3>What causes a rise in the oxidation number?</h3>

An increase in oxidation number results from the loss of negatively charged electrons, whereas a reduction in oxidation number results from the gain of electrons. The result is a rise in the oxidation number of the oxidized element or ion.

<h3>Pattern of the Period 2?</h3>

The trends in Period 2 are significantly more clear-cut. All elements in period 2 experience a decrease in atomic radius, an increase in electronegativity, and an increase in ionization energy as their atomic number rises.

To know more about Periodic table please click here : brainly.com/question/15987580

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5 0
1 year ago
How many moles of  dipyrithione contain 8.0 x 10^24 atoms of N?
kirza4 [7]
8E24/6.022E23= 13.28 moles, where the denominator is Avagadro's number
8 0
3 years ago
Visible light is a part of what spectrum
Volgvan

Answer:

Visible Spectrum/Electromagnetic spectrum

Explanation:

The visible spectrum is the portion of the electromagnetic spectrum that is visible to the human eye.

6 0
2 years ago
Plz help I’ll mark brainliest
mylen [45]

B

greenhouse effect describes Earth's atmosphere trap heat

3 0
3 years ago
Read 2 more answers
Compute the electrical conductivity of cylindrical silicon specimen 5.1 mm (0.2 in.) in diameter and 51 mm (2 in.) in length in
zhannawk [14.2K]

Answer:

Therefore electric conductivity \sigma=1.46  (Ω-m)⁻¹

Explanation:

\sigma=\frac{1}{\rho} =\frac{Il}{VA}

Here σ= electrical conductivity

        I = current = 0.1 A

        l= length= 38 mm= 38×10⁻³ m

       v= voltage = 12.5 V

      A = area = \pi(\frac{d}{2} )^{2} = \pi (\frac{51\times 10^{-3}}{2} )^2 m²

\sigma=\frac{(0.1)\times 38\times 10^{-3}}{12.5\times \pi (\frac{51\times 10^{-3}}{2} )^2 }

  =1.46 (Ω-m)⁻¹

Therefore electric conductivity \sigma=1.46  (Ω-m)⁻¹

3 0
3 years ago
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