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PolarNik [594]
3 years ago
9

Which of the following are examples of compounds? CO2 H2O С Au

Chemistry
2 answers:
Artyom0805 [142]3 years ago
7 0
CO2 and H2O are compounds hope this helped :)
katrin2010 [14]3 years ago
4 0

Answer: C02, & H20, are both examples of compounds. Hope this helps!

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How many grams of F are in 12.56 g of SF6? h.
natali 33 [55]

Answer:

9.80 g

Explanation:

The molecular mass of the atoms mentioned in the question is as follows -

S = 32 g / mol

F = 19 g / mol

The molecular mass of the compound , SF₆ = 32 + ( 6 * 19 ) = 146 g / mol

The mass of 6 F = 6 * 19 = 114 g /mol .

The percentage of F in the compound =

mass of 6 F / total mass of the compound * 100

Hence ,  

The percentage of F in the compound = 114 g /mol  / 146 g / mol * 100

78.08 %

Hence , from the question ,

In 12.56 g of the compound ,

The grams of F = 0.7808 * 12.56 = 9.80 g

4 0
3 years ago
True or false? Steel is a chemical element.
Irina-Kira [14]
I think answer is false
8 0
3 years ago
Read 2 more answers
Which element would mostly have chemical properties similar to that of magnesium (Mg)?
DanielleElmas [232]

The elements of same group are placed in same group as they have similar properties. So Calcium is the element which resembles Mangesium.

Calcium and Magnesium both are alkaline earth metals.

They have similar properties as they have similar outer or valence shell electronic configuration

The general electronic configuration of alkaline earht metal is ns2

The electronic configuration of Mg [atomic number 12] and Ca [atomic number 20] are

[Ne]3s^{2}  and [Ar]4s^{2} respectively.


7 0
3 years ago
THE ANSWER IS <br> Magnesium hydroxide (Mg(OH)2): 58.33<br><br> Iron(III) oxide (Fe2O3): 159.70
dangina [55]

Answer:

Ok, thanks?

Have a good day

5 0
3 years ago
Use Boyle’s law to complete the following:
mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

          V1P1 = V2P2

Clear V2 from the formula

            V2 = V1P1/P2

Substitution

            V2 = (0.5)(1)/2  substitution

                  = 0.25 l       result

3 0
3 years ago
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