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3 years ago

The final image from a simple two-lens telescope is:

1 answer:

s2008m [1.1K]3 years ago

4 0

A telescope with only one lens is built to photograph with.

A telescope with two lenses is built to look through. It produces
an image for your eye to look at. The image is virtual and inverted.

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Three charges lie along the x axis. The positive charge q1 = 15 μC is at x= 2.0 m and the positive charge q2 = 6.0μC is at the o

Delicious77 [7]

Answer:

x = 0.775m

Explanation:

Conceptual analysis

In the attached figure we see the locations of the charges. We place the charge q₃ at a distance x from the origin. The forces F₂₃ and F₁₃ are attractive forces because the charges have an opposite sign, and these forces must be equal so that the net force on the charge q₃ is zero.

We apply Coulomb's law to calculate the electrical forces on q₃:

$F_{23} = \frac{k*q_{2}*q_{3}}{x^2}$ (Electric force of q₂ over q₃)

$F_{13} = \frac{k*q_{1}*q_{3}}{(2-x)^2}$ (Electric force of q₁ over q₃)

Known data

q₁ = 15 μC = 15*10⁻⁶ C

q₂ = 6 μC = 6*10⁻⁶ C

Problem development

F₂₃ = F₁₃

$\frac{k*q_{2}*q_{3}}{x^2} = \frac{k*q_{1}*q_{3}}{(2-x)^2}$ (We cancel k and q₃)

$\frac{q_2}{x^2}=\frac{q_1}{(2-x)^2}$

q₂(2-x)² = q₁x²

6×10⁻⁶(2-x)² = 15×10⁻⁶(x)² (We cancel 10⁻⁶)

6(2-x)² = 15(x)²

6(4-4x+x²) = 15x²

24 - 24x + 6x² = 15x²

9x² + 24x - 24 = 0

The solution of the quadratic equation is:

x₁ = 0.775m

x₂ = -3.44m

x₁ meets the conditions for the forces to cancel in q₃

x₂ does not meet the conditions because the forces would remain in the same direction and would not cancel

The negative charge q₃ must be placed on x = 0.775 so that the net force is equal to zero.

6 0

3 years ago

Read 2 more answers

What is thermal equilibrium?

FrozenT [24]

Thermal equilibrium is a state in which all parts of a system are at the same temperature

3 0

3 years ago

Which would most likely have a direct effect on using wave power to generate electricity?

Nadya [2.5K]

Answer: I would either say wind or sunlight

Explanation:

I don’t think it would be clouds or rain

Hope that helps

4 0

3 years ago

Read 2 more answers

You see a lightning bolt flash in the distant sky. You hear the corresponding thunder 6.8 seconds later. If the temperature is 2

Anna35 [415]

Answer:

$Distance = 2.4\ km$

Explanation:

Given

$Time (t) = 6.8s$

$Temperature = 28C$

Required

Determine the distance at which the lighting struck

First, we need to determine the speed at which the lighting struck because the peed of sound varies with temperature.

At about 28C, the speed of sound is 346m/s

So, we have the following:

$Speed = 346m/s$

$Time = 6.8s$

Distance is calculated as thus:

$Distance = Speed * Time$

$Distance = 346m/s * 6.8s$

$Distance = 2352.8$

Divide by 1000 to get distance equivalent in kilometers

$Distance = \frac{2352.8km}{1000}$

$Distance = 2.3528km$

$Distance = 2.4\ km$ ---- Approximated

7 0

3 years ago

A horizontal disk with a radius of 23 m rotates about a vertical axis through its center. The disk starts from rest and has a co

lys-0071 [83]

Answer:

time is 0.42 sec

Explanation:

Given data

radius = 23 m

angular acceleration = 5.7 rad/s²

to find out

time

solution

we know that radius is constant so that

tangential acceleration At = angular acceleration × radius ............. 1

tangential acceleration = 5.7 × 23 = 131.1 m/s²

and

radial acceleration Ar = (angular velocity)² × radius ........................2

we consider angular velocity = ω

this is acting toward center

compare 1 and 2

At = Ar

5.7 r =ω³ r

ω = √5.7 = 2.38746 rad/s

ω = 5.7 t

2.387 = 5.7 t

t = 2.387 / 5.7

t = 0.4187

time is 0.42 sec

8 0

3 years ago