1. They could have different types of sounds, so wave-shape could be different.
2. If they have the same frequency, the volume is different, so they could have different amplitudes (larger amplitude = larger sound).
3. Different frequencies based on the pitches
Answer: 42 N-s
Explanation: The area under the curve is equal to the impulse, so you take the area of the two triangles and add it to the area of the rectangle.
Area of a triangle: 1/2bh
Area of a rectangle: bxh
2(1/2x2x7)=14+(4x7)=42 N-s
Answer:
Sodium sulfate(Na2SO4) is a salt
Explanation:
It is a neutralization reaction in which sulphuric acid (H2SO4) which is composed of sulfur, oxygen, and hydrogen. Sulphuric acid is strong acid reacts with 2 moles of Sodium hydroxide (in neutralization reaction 1 mole of sulphuric acid is equal to 2 moles of Sodium hydroxide) gives us 2 moles of water and sodium sulfate (Na2SO4) which is composed of sodium, sulfur, and oxygen.
Sodium sulfate (Na2SO4) is salt, when H2SO4 reacts with sodium hydroxide (due to hydrate) it will give us salt (Na2SO4)
Answer:
The shift the threshold wavelength for photoelectric emission is 2.317 nm.
Explanation:
Given that,
Work function = 5.22 eV
Temperature = 25°C
Increased temperature = 300°C
Drop work function = 50 meV
We need to calculate the shift the threshold wavelength for photoelectric emission
Using formula of work function
The wavelength for initial temperature,
The wavelength for final temperature,
The change in wavelength is
Put the value into the formula
Hence, The shift the threshold wavelength for photoelectric emission is 2.317 nm.
Answer:
<h3>25km/hr</h3>
Explanation:
Velocity is the change in displacement of a body with respect to time.
Velocity - Displacement/time
Given
displacement = 76km
Time = 3hours
Substitute the given parameters into the formula;
Velocity = 75km/3hrs
Velocity = 25km/hr
Hence the velocity of the narwhal is 25km/hr