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3 years ago

What determines how the plates interact at their boundaries

Physics

1 answer:

swat323 years ago

3 0

Answer:

Tectonic plate interactions are of three different basic types: Divergent boundaries are areas where plates move away from each other, forming either mid-oceanic ridges or rift valleys. These are also known as constructive boundaries. Convergent boundaries are areas where plates move toward each other and collide.

Explanation:

Meaning the answer to your question is depending on what type of tectonic plate interaction is occurring will depend on how the plates interact.

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Light with a wavelength of 612 nm incident on a double slit produces a second-order maximum at an angle of 25 degree. What is th

erastova [34]

Answer:

Speration between the slits $d=2.86\ \mu m$

Explanation:

Given that,

Wavelength of light, $\lambda=612\ nm=612\times 10^{-9}\ m$

It is incident on a double slit produces a second-order maximum at an angle of 25 degree.

The condition for maxima is given as :

$dsin\theta=m\lambda$

d = seperation between the slits

m = order, m = 2

$d=\dfrac{m\lambda}{sin\theta}$

$d=\dfrac{2\times 612\times 10^{-9}\ m}{sin(25)}$

d = 0.00000289

$d=2.86\mu m$

So, the seperation between the silts is $2.86\ \mu m$ . Hence, this is the required solution.

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3 years ago

The elements that are considered very reactive are part of which family

s344n2d4d5 [400]

#ClutchMoments lol !

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3 years ago

The two main currents that affect the united states on the eat coast and west coast

Virty [35]

<span>The California current on the west coast which runs from north to south and the Gulf Stream on the East coast which runs from south to north.</span>

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2 years ago

Read 2 more answers

Singing that is off-pitch by more than about 1% sounds bad. How fast would a singer have to be moving relative to the rest of a

Nina [5.8K]

Answer:

-3.396 m/s or 3.465 m/s

Explanation:

v = Speed of sound in air = 343 m/s

$v_s$ = Relative speed of the singer

f = Observed frequency

f' = Actual frequency

1% change can mean $f=1.01f'$

From the Doppler effect equation we have

$f=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{1.01}-343\\\Rightarrow v_s=-3.396\ m/s$

The velocity is -3.396 m/s

when $f=0.99f'$

$f=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{0.99}-343\\\Rightarrow v_s=3.46464646465\ m/s$

The velocity is 3.465 m/s

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2 years ago

A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of

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Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)

Explanation:

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2 years ago