Will give brainliest!!! A. 2 B. 3 C. 4 D. 5

Rama09 [41]

A trapezoid with legs MN = FD is an isosceles trapezoid.
An isosceles trapezoid has diagonals that are congruent, therefore: MF = ND.
A quadrilateral with diagonals congruent and perpendicular is a square.
In a square, the height coincides with the side.
The area of a square is given by A = s²
Therefore, the area of MNFD is h²

6 0

3 years ago

Directed line segment AB has endpoints A(2,3) and B(8,15). Point P has coordinated P(6,11). What ratio does P partition AB into?

Vladimir79 [104]

Refer to the graph shown below. It confirms that points A, B and P are
collinear.

Calculate the length of AP (as a).
a = √[(6 - 2)² + (11 - 3)²]
= 8.9443

Calculate the length of BP (as b).
b = √[(8 - 6)² + (15 - 11)²]
= 4.4721

Calculate ratio a/b.
a/b = 8.9443/4.4721 = 2
Therefore P partitions AB in a 2:1 ratio so that AP = 2*BP.

Answer: 2:1 ratio.

7 0

3 years ago

Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?

valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0

4 years ago

the figure below shows two half-circles at the ends of a rectangle with the dimensions shown. which is the closet to the area of

Pani-rosa [81]

You get 92.56 You add the area of the rectangle to the area of a circle

8 0

4 years ago

The Bureau of Labor Statistics1 in the US tells us that, in 2010, the unemployment rate for high school graduates with no colleg

mars1129 [50]

Answer:

$p_1 -p_2 = 0.097-0.052 = 0.045$

So then the difference between the two proportions is 0.045 and if we convert this into % we got

$0.045*100= 4.5%$

Step-by-step explanation:

For this case we can define the following notation:

$p_1$ represent the unemployment rate for high school graduates with no college degree

$p_2$ represent the unemployment rate for college graduates with a bachelor's degree

And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:

$p_1 -p_2$

From the info given we have $p_1 = \frac{9.7}{100}=0.097$

$p_2 = \frac{5.2}{100}=0.052$

And the difference:

$p_1 -p_2 = 0.097-0.052 = 0.045$

So then the difference between the two proportions is 0.045 and if we convert this into % we got

$0.045*100= 4.5%$

5 0

3 years ago