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4 years ago

Organs join to form a(n) ____________________ that performs a major function.

Chemistry

2 answers:

sleet_krkn [62]4 years ago

8 0

Organs join to form an "Organism" that performs a major function.

Hope this helps!

Julli [10]4 years ago

4 0

Organisms is the answer your looking for

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A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is $1.3\times 10^2g$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

5 0

3 years ago

A sealed piston contains 400 mL of air at standard ambient pressure. The piston is

nydimaria [60]

Answer:

324.24 kPa

Explanation:

Given that;

Initial pressure P1 = 101325 Pa

V1= 400 ml

P2 = ?

V2= 125mL

From Boyle's law;

P1V1 = P2V2

P2 = P1V1/V2

P2= 101325 × 400/125

P2= 324.24 kPa

5 0

3 years ago

How does the arrangement of atoms in a crystalline substance differ from the arrangement in a noncrystalline (amorphous) substan

Lady bird [3.3K]

Answer:

4. Atoms in crystals are in an ordered array. In amorphous materials, they are randomly distributed.

Explanation:

3 0

3 years ago

How does an increase in concentration affect a chemical reaction? (3 points)

Firlakuza [10]

Answer:

Explanation:

1. Increasing the concentrations of reactants in a chemical reaction would affect a reaction positively by increasing the number of collisions within a particular period which in turn increases the rate of reaction.

2. The molecules gains energy,which enable them to move faster and collide with the right energy for a reaction to take place.

3. The average kinetic motion of molecules in a solution can be measured by measuring the temperature. Temperature is a measure of the average kinetic energy of molecules in a solution.

4 0

4 years ago

if 193 ml of chlorine gas was collected at 21 celsius, what volume would it have if the temperature dropped to 0 celsius

Advocard [28]

Answer:

New volume of chlorine gas (V2) = 179 ml (Approx)

Explanation:

Given:

Volume of chlorine gas (V1) = 193 ml

Temperature of chlorine gas (T1) = 21°C = 21 + 273 = 294 k

New temperature of chlorine gas (T2) = 0°C = 0 + 273 = 273 k

Find:

New volume of chlorine gas (V2) = ?

Computation:

Using charle's law

V1 / T1 = V2 / T2

193 / 294 = V2 / 273

V2 = 179.21

New volume of chlorine gas (V2) = 179 ml (Approx)

6 0

3 years ago