Since A is (-7,-4) and C is (7,3) for the x value from a to c is 14 for the y value from a to c is 7
Do 14 x 2/7 which is 4
Do 7 x 2/7 which is 2
then add (-7+4,-4+2) which is (-3,-2)
624 is how much is deducted from his pay every month
Answer:
The 90% confidence interval for population mean is 
Step-by-step explanation:
From the question we are told that
The sample mean is 
The confidence level is 
The sample size is 
The standard deviation
Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as


Next we obtain the critical value of
from the standardized normal distribution table. The values is 
The reason we are obtaining critical values for
instead of that of
is because
represents the area under the normal curve where the confidence level 1 -
(90%) did not cover which include both the left and right tail while
is just considering the area of one tail which is what we required calculate the margin of error
Generally the margin of error is mathematically evaluated as

substituting values


The 90% confidence level interval is mathematically represented as

substituting values



Answer:
Is their an equation that can be used a reference to find the sum/difference/product/quotient to this equation?
Step-by-step explanation:
A) because when they are equal it means that their y has the same value, which means their intersection point.
B) You should take all integers from (-2, 2) which are: -2, -1, 0, 1, 2 and put them one by one in the example:
x = -2
y1 = 4^-(-2) = 4^2 = 16
y2 = 2^(-(-2) + 1) = 2^(2+1) = 2^3 = 8
y1 ≠ y2 => so x=-2 isn't our answer
-------------------------------------------------------
x = -1
y1 = 4^-(-1) = 4^1 = 4
y2 = 2^(-(-1) + 1) = 2^(1+1) = 2^2 = 4
y1 = y2 => so our answer will be x = -1
-------------------------------------------------------
x = 0
y1 = 4^-(0) = 4^0 = 1
y2 = 2^(-(0) + 1) = 2^(0+1) = 2^1 = 2
y1 ≠ y2 => so x=0 isn't our answer
--------------------------------------------------------------
x = 1
y1 = 4^-(1) = 4^(-1) = 1/4
y2 = 2^(-(1) + 1) = 2^(-1+1) = 2^0 = 1
y1 ≠ y2 => so x=1 isn't our answer
--------------------------------------------------------------
x = 2
y1 = 4^-(2) = 4^(-2) = 1/16
y2 = 2^(-(2) + 1) = 2^(-2+1) = 2^(-1) = 1/2
y1 ≠ y2 => so x=2 isn't our answer
Which means that our final answer is: x=-1
C) You should draw both graphics, and their intersection point (x) will be the answer.
I hope it helped.