All categories

3 years ago

If i have a square garden with an area of 50 sq feet how can i figure out how long each side is?

Mathematics

1 answer:

serg [7]3 years ago

8 0

Answer:

a=l×w 50=l×w if it could be multiple answers unless you have more info on l or w

You might be interested in

Ann Zoe and Jim bought a present for ben. Ann cooperated with $12 less than Zoe and $16 less than Jim. If the cost of the presen

sergeinik [125]

Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.

Ann (A): A

Zoe (Z): A = Z - 12 → Z = 12 + A

Jim (J): A = J - 16 → J = 16 + A

A + Z + J = 154

(A) + (12 + A) + (16 + A) = 154

3A + 28 = 154

3A = 126

A = 42

Ann (A): A = 42

Zoe (Z): Z = 12 + A = 12 + 42 = 54

Jim (J): J = 16 + A = 16 + 42 = 58

Answer: Ann=42, Zoe=54, Jim=58

6 0

2 years ago

Consider each equation. is it the equation of the line that is parallel or perpendicular to y=3x+2? Select yes or no for a-c

Mkey [24]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 2 is in this form with slope m = 3

• Parallel lines have equal slope

• The slopes of perpendicular lines are negative reciprocals of each other

y = - $\frac{1}{3}$ x - 8 has slope m = - $\frac{1}{3}$

3 and - $\frac{1}{3}$ are negative reciprocals

This line is perpendicular to y = 3x + 2

y = 3x - 10 has slope m = 3

This line is parallel to y = 3x + 2

y = 2x + 4 has slope m = 2

This line is neither parallel nor perpendicular to y = 3x + 2

5 0

3 years ago

Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen

Irina-Kira [14]

Hi there!

PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)

Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1

PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.

Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers

ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

8 0

3 years ago

Bezzdna [24]

Answer:

120

Step-by-step explanation:

udidjhwvwuwiwhg123

6 0

2 years ago

Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade. Mrs. Benson has how many math assignmen

timofeeve [1]

Mrs. Benson has 184 math assignments left to grade.

<u>Step-by-step explanation:</u>

Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:

Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.

⇒ $x = 46+\frac{80x}{100}$