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3 years ago

What is the smallest number of products in a decomposition reaction?

Chemistry

2 answers:

KengaRu [80]3 years ago

8 0

The answer would be two

AysviL [449]3 years ago

8 0

I believe two is the answer

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Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth miles. Such massive ships require a dista

uranmaximum [27]

Answer:

Acceleration = (change in speed) / (time for the change)

Change in speed= (0 - 26 km/hr) = -26 km/hr

(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec

Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²

Average speed during the stopping maneuver =

(1/2) (start speed + end speed) = 13 km/hr = 3.6111 m/sec

Explanation:

4 0

3 years ago

Match the following with their correct molecular weight. 2-butanone Propyl acetate 4-methyl-2-pentanone Butyl acetate Methanol E

Hatshy [7]

Answer:

2-butanone = 72.11 g/mol (option F)

Propyl acetate = 102.13 g/mol (option C)

4-methyl-2-pentanone = 100.16 g/mol (option D)

Butyl acetate = 116.16 g/mol (option B)

Methanol = 32.04 g/mol (option E)

Ethanol = 46.07 g/mol (option A)

Explanation:

Step 1: Data given

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Step 2:

2-butanone = C4H8O

⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)

Propyl acetate = C5H10O2

⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)

4-methyl-2-pentanone = C6H12O

⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)

Butyl acetate = C6H12O2

⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)

Methanol = CH3OH = CH4O

⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)

Ethanol = C2H5OH = C2H6O

⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)

4 0

3 years ago

When a chemical recstion has oxygen what does it clasify as

Murrr4er [49]

Answer: Combustion.

Explanation:

7 0

3 years ago

__ CaSO4 + ____AIP --> ____Ca3P2 + ____AI2(SO4)3

4vir4ik [10]

Answer:

4.89 mol

Explanation:

Step 1: Write the balanced equation

This is a double displacement reaction.

3 CaSO₄ + 2 AIP ⇒ Ca₃P₂ + AI₂(SO₄)₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CaSO₄ to AlP is 3:2.

Step 3: Calculate the moles of AlP needed to react with 7.33 moles of CaSO₄

We will use the previously established molar ratio.

7.33 mol CaSO₄ × 2 mol AlP/3 mol CaSO₄ = 4.89 mol AlP

3 0

3 years ago

Of the reactions below, only ________ is not spontaneous. A. Zn (s) + 2HI (aq) → ZnI2(aq) + H2 (g) B. 2Ag (s) + 2HNO3 (aq) → 2Ag

Fynjy0 [20]

Answer:

2Ag (s) + 2HNO3 (aq) → 2AgNO3 (aq) + H2(g)

Explanation:

Usually, metals displace hydrogen from dilute acids to form the corresponding salt of the metal and hydrogen. This in turn depends on the position of the metal in the electrochemical series. Metals below hydrogen in the electrochemical series cannot spontaneously displace it from dilute acids. Silver is below hydrogen in the electrochemical series, hence it cannot spontaneously displace hydrogen from dilute nitric acid as shown in the answer.

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3 years ago