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Andrew [12]
3 years ago
12

1. Convert the following temperatures to K. a) 104 C b) -3 C

Chemistry
1 answer:
gogolik [260]3 years ago
3 0

Answer:

a) 377 k

b) 270 k

Explanation:

a) 104 + 273 = 377 k

b) -3 + 273 = 270 k

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Question 12 (1 point)
Vinvika [58]

Answer:

Option c. Neutral

Explanation:

Only neutral solution gives a green colouration to a pH paper

8 0
3 years ago
Read 2 more answers
How many molecular of H2O and O2 are present in 8.5g of H2O2 ?​
Mama L [17]

2H2O+O2--->2H2O2  

8.5 gm H2O2=0.25 mole  

hence H2O is also 0.25 mole i.e.4.5 gm  

O2is 0.125 mole i.e.4 gm

4 0
3 years ago
A balloon is filled to a volume of 700 mL at a pressure of 1.2 atm. The volume is increased 950 ml, what will be the new pressur
konstantin123 [22]
P1V1 = P2V2

1.2ATM*(.7 L) = V2 * .95L

V2 = 0.884 Liters or 884.21 ml
3 0
2 years ago
How can mass and energy behave in an open system
algol13
An open system<span> is a system that has external interactions.</span>
3 0
3 years ago
2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2
Sergeu [11.5K]

Answer: 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{1.60g}{32g/mol}=0.05moles

2KMnO_4\rightarrow K_2MnO_4+MnO_2+O_2

According to stoichiometry :

As 1 mole of O_2 is given by = 2 moles of KMnO_4

Thus 0.05 moles of O_2 is given by =\frac{2}{1}\times 0.05=0.10moles  of KMnO_4

Mass of KMnO_4=moles\times {\text {Molar mass}}=0.10moles\times 158g/mol=15.8g

Thus 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

5 0
3 years ago
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