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3 years ago

1. Convert the following temperatures to K. a) 104 C b) -3 C

Chemistry

1 answer:

gogolik [260]3 years ago

3 0

Answer:

a) 377 k

b) 270 k

Explanation:

a) 104 + 273 = 377 k

b) -3 + 273 = 270 k

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What volume of 3.00 MM HClHCl in liters is needed to react completely (with nothing left over) with 0.750 LL of 0.500 MM Na2CO3N

AlladinOne [14]

Answer: The volume of HCl needed is 0.250 L

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

For sodium carbonate:

Molarity of sodium carbonate solution = 0.500 M

Volume of solution = 0.750 L

Putting values in above equation, we get:

$0.500M=\frac{\text{Moles of sodium carbonate}}{0.750}\\\\\text{Moles of sodium carbonate}=(0.500mol/L\times 0.750L)=0.375mol$

The chemical equation for the reaction of sodium carbonate and HCl follows:

$Na_2CO_3+2HCl\rightarrow 2NaCl+H_2CO_3$

By Stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 2 moles of HCl

So, 0.375 moles of sodium carbonate will react with = $\frac{2}{1}\times 0.375=0.750mol$ of HCl

Now, calculating the volume of HCl by using equation 1:

Moles of HCl = 0.750 moles

Molarity of HCl = 3.00 M

Putting values in equation 1, we get:

$3.00M=\frac{0.750mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.750mol}{3.00mol/L}=0.250L$

Hence, the volume of HCl needed is 0.250 L

8 0

3 years ago

What is the temperature of 0. 750 mol of a gas stored in a 6,850 ml cylinder at 2. 21 atm?.

victus00 [196]

-246 K-

________________

3 0

2 years ago

Atoms that have the same number of outer electrons

BARSIC [14]

I can see two answers, I’d go with D, but all neutral atoms, of the same element would have the same number of outer electrons. However, if you consider that some of the atoms might be ions, that would eliminate B.

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When a drawing of a circle made in the center of a piece of paper with a black marker gets wet, the marker bleeds, and as the wa

Ahat [919]

Answer:

Chromatography

Explanation:

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Solve the enthalpy of formation NH3(g) -46.11

lora16 [44]

I think 43.12 I’m not that good with math

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