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mestny [16]
3 years ago
11

Fred the clown can create 20 animal balloons every 15 minutes. How much can he create in 6 minutes, and 45 minutes?

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0

\bf \textit{\Large in 6 minutes}\\\\ \begin{array}{ccll} balloons&minutes\\ \cline{1-2} 20&15\\ x&6 \end{array}\implies \cfrac{20}{x}=\cfrac{15}{6}\implies 120=15x \\\\\\ \cfrac{120}{15}=x\implies 8=x \\\\[-0.35em] ~\dotfill\\\\ \textit{\Large in 45 minutes}\\\\ \begin{array}{ccll} balloons&minutes\\ \cline{1-2} 20&15\\ x&45 \end{array}\implies \cfrac{20}{x}=\cfrac{15}{45}\implies \cfrac{20}{x}=\cfrac{1}{3}\implies 60=x

Nikolay [14]3 years ago
3 0

Answer:



Step-by-step explanation:

If he creates 20 animal balloons in every 15 minutes, we can reveal the number of the balloons created depending on the given time.

For 6 minutes:

20 balloons   in     15 minutes

x balloons      in     6 minutes

-> We can conclude that 20(6) = x(15) -> x = 8 balloons

For 45 minutes:

20 balloons   in     15 minutes

y balloons      in     45 minutes

-> We can conclude that 20(45) = y(15) -> x = 60 balloons  

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