since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

3 years ago

Find the first quartiles (Q1) of the following sets of data.

Liula [17]

Answer:

(i) 28. (ii) 34. (iii) 42.5

Step-by-step explanation:

$first \: quartiles \: = \frac{1}{4} \times sum \: of \: the \: data$

8 0

3 years ago

Which value is not located between these two numbers on the number line

ryzh [129]

We can use an approximation of pi. pi = 3.14.

sqrt(16)/4 = 4/4 = 1

2pi = 2 * 3.14 = 6.28

We need to find the number that is not between 1 and 6.28.

A pi = 3.14; 3.14 is between 1 and 6.28, so this is not the answer.

B sqrt(9) = 3; 3 is between 1 and 6.28, so this is not the answer.

C pi/9 = 3.14/9 = 0.349; 0.349 is not between 1 and 6.28, so this is the answer.

D pi^2/9 = (3.14 * 3.14)/9 = 9.86/9 = 1.095; 1.095 is between 1 and 6.28, so this is not the answer.

Answer: C pi/9

5 0

3 years ago