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3 years ago

Maggie is sitting at a table with Fred and flourence

1 answer:

3 0

well, tell maggie i said hello...and tell fred that he still owes me money from last weeks poker match.....and make sure flourence knows that everything is gonna be ok with his toe problems......thanks

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Under which of the following conditions would a chemical reaction most likely proceed at the fastest rate?

Valentin [98]

<h2>Answer:</h2>

Option A is correct

Adding an enzyme to decrease the activation energy of the reaction

<h2>Explanation:</h2>

Enzymes are the biological catalyst. They are proteins in nature. They are naturally found in humans,animals,micro-organisms,plants etc. They catalyze the chemical reactions by lowering activation energy and without being consumed in it.

6 0

2 years ago

Read 2 more answers

During an experiment, a student observes the formation of a precipitate. Why does this indicate that a chemical reaction is like

My name is Ann [436]

A. A solid forms, and there is a change of color.

8 0

3 years ago

#5.) Explain why the rock cycle is referred to as a "cycle".

Natalka [10]

The rock cycle is referred to as cycle because it repeats over and over again. The definition of cycle is a series of events that are regularly related in the same order. So with the rock cycle they stay in the same order and repeat.
Hope this helps :)

5 0

3 years ago

Read 2 more answers

How many moles of glucose can be produced

Arturiano [62]

Answer:

moles of glucose

<u>2.3166 moles of glucose</u>

<u></u>

Explanation:

The balance reaction for the formation of glucose is :

$6CO_{2}+6H_{2}O\rightarrow C_{6}H_{12}O_{6}+6O_{2}$

here , CO2 = carbon dioxide

H2O = water

C6H12O6 = glucose

O2 = Oxygen

According to this equation :

6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2

We are asked to calculate the mole of Glucose from carbon dioxide.

So,

6 mole of CO2 produce = 1 mole of C6H12O6

1 mole of CO2 will produce =

$\frac{1}{6}$ moles of glucose

13.9 moles of CO2 will produce :

$\frac{1}{6}\times 13.9$

=2.3166 moles of glucose

Note : first , Always calculate for one mole (By dividing)

. After this , multiply the answer with the moles given.

Always write the substance whose amount is asked(glucose) to the right hand side

5 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

2 years ago