Answer:
0.55 mol Au₂S₃
Explanation:
Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.
1. Gather all the information in one place:
M_r: 34.08
Au₂S₃ + … ⟶ 3H₂S + …
m/g: 56
2. Calculate the moles of H₂S
Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)
= 1.64 mol H₂S
3. Calculate the moles of Au₂S₃
The molar ratio is 1 mol Au₂S₃/3 mol H₂S.
Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)
= 0.55 mol Au₂S₃
Unfortunately, you haven't shared any data list which would make braunly users able to help you. The only thing I can suggest you is to write the neutralization reactions, this can make you understand the calculations more or less clearly. Please, next time check your attachments carefully.
Characteristic properties are used because the sample size and the shape of the substance does not matter.
140 s. It would take 140 s to swim 0.150 mi
.
<em>Step 1</em>. Convert the <em>time to seconds</em>
Time = 14 min × (60 s/1 min) + 34.56 s = 840 s + 34.56 s = 874.56 s
<em>Step 2</em>. Convert <em>miles to metres
</em>
Distance = 0.150 mi × (1609.3 m/1 mi) = 241.4 m
<em>Step 3.</em> Calculate the <em>time to swim 241.4 m</em>
Time = 241.4 m × (874.56 s/1500 m) = 140 s
(<em>As of 2012, the men’s freestyle record for 1500 m was 14:31.02</em>.)