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vodomira [7]
3 years ago
7

Two descriptions about physical quantities are given below:

Chemistry
2 answers:
gladu [14]3 years ago
8 0

Answer:

Quantity A is weight and Quantity B is mass

Explanation: weight has same unit as force. Mass is the quantity of matter present in a body or object

Mumz [18]3 years ago
3 0

Answer:

Quantity A is weight and Quantity B is mass

Explanation:

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If you had 6 moles of CaCl2 and 5 moles of Na3PO4, which of these would be the limiting and excess reactant
faltersainse [42]

Answer:

Na3PO4 is excess reactant, CaCl2 is limiting reactant.

Explanation:

                                      3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl

from reaction :              3 mol        2 mol

given:                            6 mol         5 mol (X)

X = (6*2)/3 = 4 mol Na3PO4

For 6 mol CaCl2 we need 4 mol Na3PO4, but  we have 5 mol Na3PO4,

Na3PO4 is excess reactant, so CaCl2 is limiting reactant.

8 0
3 years ago
Which of the following pieces of information about the element lithium describes the atomic number only
vagabundo [1.1K]
The top left corner shows the atomic number which is 3.
6 0
3 years ago
Which subshell holds the valence electrons of barium?.
olga2289 [7]

Answer:

6s

Explanation:

Barium is in group 2 of the s block and is in period 6.

7 0
2 years ago
I need help FAST ASAP
kiruha [24]
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1.  Na⁺     ,    Cl⁻    , NaCl   ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺       , O²⁻     , CO₂  ---> carbon dioxide

3. Al³+     , Cl⁻       , AlCl₃   ----> aluminum chloride

4. Ca²⁺     , Cl⁻     , CaCl₂    ---> calcium chloride

5. Li⁺        , Br⁻      , LiBr       ---> lithium bromide

6. Mg³⁺     , O²⁻      , Mg₂O₃   ----> magnesium oxide

7. K⁺        , I⁻          , KI   ---> potassium iodide

8. H⁺        , Cl⁻        , HCl  --> hydrogen chloride

9. H⁺        , Br⁻         , HBr ----> hydrogen bromide

10. Na⁺    , Br⁻         , NaBr   ---> sodium bromide
6 0
3 years ago
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
Anton [14]

Answer:-  2.4 mol NO_2 .

Solution:- It asks to calculate the moles of NO_2 formed when 1.2 moles of N_2O_5 are reacted.

There is 2:4 mol ratio between N_2O_5 and NO_2 . So, the moles of reactant are multiplied by the mol ratio to get the moles of NO_2 . The calculations are shown below:

1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})

= 2.4 mol NO_2

So, 2.4 moles of NO_2 are formed when 1.2 moles of  N_2O_5 were reacted.

7 0
3 years ago
Read 2 more answers
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