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3 years ago

A cylinder, with a piston pressing down with a constant pressure, is filled with 1.90 moles of a gas (n1),

Chemistry

1 answer:

Alexandra [31]3 years ago

7 0

Answer:

31.58 L

Explanation:

From the question given above, the following data were obtained:

Initial mole (n₁) of gas = 1.90 moles

Initial volume (V₁) = 40 L

Final mole (n₂) = 1.90 – 0.40 = 1.5 moles

Final volume (V₂) =.?

The final volume of the gas can be obtained as follow;

V₁ / n₁ = V₂ / n₂

40 / 1.9 = V₂ / 1.5

Cross multiply

1.9 × V₂ = 40 × 1.5

1.9 × V₂ = 60

Divide both side by 1.9

V₂ = 60 / 1.9

V₂ = 31.58 L

Thus, the final volume of the gas is 31.58 L

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How many grams of oxygen are required to react with 2.7 g of dihydrogen sulfide

KatRina [158]

Answer:

Mass = 3.84 g

Explanation:

Given data:

Mass of hydrogen sulfide = 2.7 g

Mass of oxygen required = ?

Solution:

Chemical equation:

2H₂S + 3O₂ → 2H₂O + 2SO₂

Number of moles of hydrogen sulfide:

Number of moles = mass/ molar mass

Number of moles = 2.7 g / 34 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of hydrogen sulfide with oxygen.

H₂S : O₂

2 : 3

0.08 : 3/2 ×0.08 = 0.12 mol

Mass of oxygen;

Mass = number of moles × molar mass

Mass = 0.12 mol × 32 g/mol

Mass = 3.84 g

3 0

4 years ago

Calculate the pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl .

Nitella [24]

Answer: 7

Explanation:

50 ml 0.125 M KOH = (50 * 0.125) = 6.25 ml 1 M KOH

similarly 50 ml 0.125 M HCl = 6.25 ml 1 M HCl

so KOH will fully neutralize the HCl so the pH of the medium will be 7

H+ + OH- = H2O

so Kw = [H=][OH-]

= [H+]^2 = 10-14

SO [H+] = 10-7

pH = -log [H+]

pH = -log[10-7]

pH = 7

6 0

3 years ago

How many molecules are contained in a 7.20-g sample of dimethylmercury?

jekas [21]

The formula for dimethyl mercury is. HgC2H6 = (2x12) + (6x1) + (1x200.6) = 230.6
So the molar mass of dimethyl mercury is 230.6 g/mol.
Number of moles in 4.2g of dimethymercury = 4.2/ 230.6 = 0.0182 moles.
1 moles of dimethymercury contains 6.02 * 10^23
Hence 0.0182 moles contains X
X = 0.0182 * 6.02 * 10^23 = 0.10952 * 10^23 = 1.0952 * 10^22.

3 0

3 years ago

Read 2 more answers

How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor

Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0

4 years ago

For each pair of salts, determine which of the salts, if any, would be expected to be more soluble in acidic solution than in pu

gogolik [260]

Answer:

AgNO2

Explanation:

The question asks to know which of these two insoluble salts is expected to be more soluble in acidic solution than in pure water.

To answer this question specifically, we need to know if the anions contained in the insoluble salt is a conjugate of a weak acid or that of a weak base.

Generally, the solubility of insoluble salts that contain anions which are conjugates of weak acids increases in the presence of an acidic solution than in water. While, the solubility of insoluble salts that contain anions which are conjugates of strong acids decreases in the presence of an acidic solution.

Having said this, AgNO2 contains NO2 which is the conjugate base of the Trioxonitrate iii acid which is a weak acid. Hence, it is expected to be stronger in acidic solution than in water.

4 0

3 years ago