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madreJ [45]
3 years ago
8

A cylinder, with a piston pressing down with a constant pressure, is filled with 1.90 moles of a gas (n1),

Chemistry
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

31.58 L

Explanation:

From the question given above, the following data were obtained:

Initial mole (n₁) of gas = 1.90 moles

Initial volume (V₁) = 40 L

Final mole (n₂) = 1.90 – 0.40 = 1.5 moles

Final volume (V₂) =.?

The final volume of the gas can be obtained as follow;

V₁ / n₁ = V₂ / n₂

40 / 1.9 = V₂ / 1.5

Cross multiply

1.9 × V₂ = 40 × 1.5

1.9 × V₂ = 60

Divide both side by 1.9

V₂ = 60 / 1.9

V₂ = 31.58 L

Thus, the final volume of the gas is 31.58 L

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Kitty [74]
The right answer for the question that is being asked and shown above is that: "<span>b. number/timed." Reaction Rate refers to the </span> speed of reaction<span> for a reactant or product in a particular </span>reaction<span> is intuitively defined as how fast or slow a</span>re action<span> takes place.</span>
4 0
3 years ago
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Which of these actions would increase heat transfer between two objects?
klasskru [66]

Heat transfer is the phenomenon that occurs when the two objects are in the vicinity of each other and by increasing the area of their contact. Thus, option B is correct.

<h3>What is heat transfer?</h3>

Heat transfer is a process that flows the heat from one system to another, and is because of the difference in the temperature of the two objects that are part of the system.

The methods like conduction, convection, and radiation transfer the heat from the surface area to the other object. The heat gets transferred from the area of high to the low temperature.

Therefore, option B. by increasing the surface area the heat transfer increases.

Learn more about heat transfer here:

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5 0
2 years ago
The standard reduction potentials of lithium metal and chlorine gas are as follows:Reaction Reduction potential(V)Li+(aq)+e−→Li(
meriva

Answer:

A) E° = 4.40 V

B) ΔG° = -8.49 × 10⁵ J

Explanation:

Let's consider the following redox reaction.

2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)

We can write the corresponding half-reactions.

Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq)      E°red = 1.36 V

Anode (oxidation):  2 Li(s) → 2 Li⁺(aq) + 2 e⁻         E°red = -3.04

<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>

The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.

E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V

<em>B) Calculate the free energy ΔG° of the reaction.</em>

We can calculate Gibbs free energy (ΔG°) using the following expression.

ΔG° = -n.F.E°

where,

n are the moles of electrons transferred

F is Faraday's constant

ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J

8 0
3 years ago
Use lewis theory to determine the formula for the compound that forms between sr and se
katen-ka-za [31]

\text{Sr}\text{Se}

<h3>Explanation</h3>

The Lewis Theory predicts the way atoms form bond based on their numbers of valence electrons. Atoms gain or lose electrons as they seek to achieve either a complete eight-electron valence shell or an empty shell, exposing the inner eight-electron shell. Both electron configurations are stable and are known as "octets". However, atoms tend to prefer the configuration with the minimum number of electron transfers.

Strontium (Sr) is found in group 2 (II A) of a modern periodic table. A neutral atom of strontium has two valence electrons in its valence shell.

Selenium (Se) is found in group 16 (VI A) of a modern periodic periodic table. A neutral atom of selenium contains six electrons in its valence shell.

Strontium needs to either lose two electrons or gain six electrons to achieve a configuration with eight electrons in its valence shell. Losing two electrons take less energy. Strontium is thus expected to lose two electrons.

Similarly, selenium would prefer gaining two electrons to losing six electrons. It is expected to gain two electrons.

As a result, a strontium atom would supply exactly two electrons. At the same time, a  As a result, a selenium atom would accept the two electrons, no more or no less. The two elements would combine at a one to one ratio. In other words:

n(\text{Sr, atoms}) : n(\text{Se, atoms}) \\= n(\text{Sr, electrons lost}) : n(\text{Se, electrons gained}) \\= 1:1

Each electron carries one negative charge. As a result, atoms that have gained electrons demonstrate a negative charge, whereas atoms that have lost electrons appear to be positive. By convention, atoms with a positive charge shall be written in front of those with a negative charge in a formula.

Sr atoms have lost electrons. Accordingly, they carry positive charges and shall be written at the beginning of the formula.

Se atoms have gained electrons. Accordingly, they carry negative charges and shall be placed to the end of the formula.

Thus the chemical formula: \text{Sr}\text{Se}

4 0
3 years ago
What is the volume of 6.78 mol of hydrogen gas at STP?
Marat540 [252]

Answer:

151.87dm³

Explanation:

Given parameters:

Volume of hydrogen gas  = 6.78mole

Unknown:

Volume of hydrogen gas formed at STP  = ?

Solution:

To solve this problem;

   1 mole of a gas at STP  = 22.4dm³ So;

   6.78 mole of gas  = 6.78 x 22.4  = 151.87dm³

7 0
3 years ago
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