If we are to draw the sulfuric acid structure based on
Lewis it would look like:
O
ll
O =
S – O –H
l
O
l
H
So from this, we can see that there are 2 double bonds (O
= S) and 4 single bonds (S – O and O – H).
Therefore the answer is:
4 single, 2 double
Answer:
Number of times a one pound (2.2 kg) block of iron can be split in half before it stops being iron
= 84.29 times
Explanation:
Atoms : It is the smallest indivisible particle of the matter .
The atom can not be further breakdown .
Here in this question , we have to find the number of atoms (because it is the last possible situation for breaking of atom)
Mole : The quantity of the substance that contain as many particles as present in 12 g of C-12.It is quantity which Avogadro number(N0) of particles

<u>1.First calculate the number of moles of Fe in 2.2Kg Block</u>
Mass of Iron (Fe) = 55.845 amu
Molar mass of Iron = 55.845 g
Given mass = 2.2 kg
1 kg = 1000 g
2.2 kg = 2200 g

![moles = \frac{2200}{55.845}Moles of Fe = 39.39 2.Calculate the number of particles of Fe in 39.39 moles of Block[tex]moles = \frac{Number\ of\ Particles}{Avogadro\ number}](https://tex.z-dn.net/?f=moles%20%3D%20%5Cfrac%7B2200%7D%7B55.845%7D%3C%2Fp%3E%3Cp%3E%3Cu%3E%3Cstrong%3EMoles%20of%20Fe%20%20%3D%2039.39%20%3C%2Fstrong%3E%3C%2Fu%3E%3C%2Fp%3E%3Cp%3E2.C%3Cu%3Ealculate%20the%20number%20of%20particles%20of%20Fe%20in%2039.39%20moles%20of%20%20Block%3C%2Fu%3E%3C%2Fp%3E%3Cp%3E%5Btex%5Dmoles%20%3D%20%5Cfrac%7BNumber%5C%20of%5C%20Particles%7D%7BAvogadro%5C%20number%7D)

moles = 39.39



atoms
<u>3.Calculate Number of time(n), the block is </u><u>split into -Half </u>
Take log both side ,

Solve for n, you get
n= 84.29 (convert it to nearest whole number)
n = 84 times
2.43 kilograms is equal to 2430 grams because 1 kilogram is equal to 1000 grams.
The sand provides a rough surface on top of the ice for the cars' tires to grip onto. It provides more friction. Salt melts the ice and often provides more friction (the disadvantage is that it eats concrete!).