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sergiy2304 [10]
3 years ago
15

Calculate the mass of a bodyWhose volume isIs 2cm3 and density is 520cm3​

Chemistry
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

The answer is

<h2>1040g</h2>

Explanation:

Density = mass / volume

mass = density × volume

volume = 2cm³

density = 520g/cm³

mass = 2 × 520

= 1040g

Hope this helps you

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Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
MrRissso [65]

Answer:

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

10^{-9,33} = [H⁺]

The volume of swimming pool is:

700'000 galllons ×\frac{3,78541 L}{1 gallon} = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

7 0
3 years ago
Question 23 (3 points)
Mice21 [21]

Answer:

<h2>The answer is 3.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of aluminum = 8.1 g

density = 2.7 g/mL

It's volume is

volume =  \frac{8.1}{2.7}  \\

We have the final answer as

<h3>3.0 mL</h3>

Hope this helps you

3 0
3 years ago
How do you separate alcoh0l from water?
Xelga [282]

Answer:

Fractional distillation

Explanation:

7 0
2 years ago
Place these elements in order of LOWEST electronegativity to HIGHEST.
mrs_skeptik [129]

Answer:

Barium

Molebdenum

Cobalt

Nitrogen

Explanation:

science

8 0
3 years ago
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What is condensation ?
fomenos

Answer:

gvapor or gas to liquid

Explanation:

water which collects as droplets on cold surface when humid air is in contact with it

3 0
3 years ago
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