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OleMash [197]
3 years ago
12

(Plz hurry) Given that cosθ=817 and sinθ=−1517 . What is the value of tanθ? 815 −815 158 −158

Mathematics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

<h2>D. -15/8</h2>

Step-by-step explanation:

Given the following;

cosθ=8/17 and sinθ=−15/17

In trigonometry identity, tanθ = sinθ/cosθ

Substituting the given values in the equation;

tan θ = (−15/17)/(8/17)

tanθ = −15 /17 * 17/8

tanθ = -15/8

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Answer:

w= 1

Step-by-step explanation:

hope this helps :)

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Answer:

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Step-by-step explanation:

Put them in a decimal, the you can find if it's in the 10ths place or 100ths place

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Country A is ten to the third power times greater than Country B. Country A has a population of 230,000,000. What is the populat
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There are 150 teachers and 50 are mathe teachers what percent are math teachers
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8 0
3 years ago
Read 2 more answers
A. Show that the vector v = ai + bj is perpendicular to the line ax + by = c by establishing that the slope of v is the negative
pishuonlain [190]

Answer:

Part A:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector = \frac{b}{a}

Step-by-step explanation:

Condition for perpendicular is:

m_1m_2=-1

Part A:

Consider the vector v = ai + bj

x component of vector=a

y component of vector=b

Slope of vector=m_1=\frac{y}{x}=\frac{b}{a}

Consider the line ax + by = c:

Rearranging the equation:

ax+by=c

by=c-ax

y=\frac{-ax}{b}+\frac{c}{b}

According to general equation of line: y=mx+c

Where m is the slope

In our case the slope of above line is:

m_2=\frac{-a}{b}

According to the condition of perpendicular:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector is also calculated above.

Since the slope of vector is negative reciprocal of the slope of the given line:

According to equation of line ax + by = c

y=\frac{-ax}{b}+\frac{c}{b}

According to  general equation of line: y=mx+c

Where m is the slope

Slope of given line=m=\frac{-a}{b}

negative reciprocal of the slope of the given line = \frac{b}{a}

Slope of vector = \frac{b}{a}

5 0
3 years ago
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