Question

A 9800-N automobile is pushed along a level road by four students who apply a total forward force of 600 N. Neglecting friction, the acceleration of the automobile is: a) 0.0 m /s^2 b) 0.54 m/s^2 c) 0.6 m/s^2 d) 9.8 m/s^2

Answer 1

Answer:

c).  $a = 0.60 m/s^2$

Explanation:

As we know that weight of the automobile is given here

so weight = mass times gravity

$W = mg$

$9800 = m(9.8)$

$m = 1000 kg$

now from Newton's law

$F = ma$

$600 = 1000 a$

$a = \frac{600}{1000}$

$a = 0.60 m/s^2$