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Lelu [443]
3 years ago
10

Imma straight male btw also wut are newtons law write a paragraph desricbing them

Physics
1 answer:
tekilochka [14]3 years ago
8 0
Third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
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Label each of the front symbols below and describe what kind of weather they can bring.
FinnZ [79.3K]

Answer:

sometimes sunset could sometimes cause a pink and orange cloud

4 0
3 years ago
a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C
Ymorist [56]

Answer:

0.02976°C

Explanation:

Heat Supplied = mcø

ø = 500/(4*4200)

ø = 0.02976 °C

3 0
3 years ago
A 50-cm-long spring is suspended from the ceiling. A 330 g mass is connected to the end and held at rest with the spring unstret
lukranit [14]

Explanation:

Given that,

Length of the spring, l = 50 cm = 0.5 m

Mass connected to the end, m = 330 g = 0.33 kg

The mass is released and falls, stretching the spring by 30 cm before coming to rest at its lowest point. On applying Newton's second law, 10 cm below the release point, x = 15 cm

(a) When the mass is connected, the force of gravity is balanced by the force in spring.

kx=mg\\\\k=\dfrac{mg}{x}\\\\k=\dfrac{0.33\times 9.8}{0.15}\\\\k=21.56\ N/m

(b) The amplitude of the oscillation will be 15 cm as it is half of the total distance travelled.

(c) The frequency of the oscillation is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{21.56}{0.33}} \\\\f=1.28\ Hz

Hence, this is the required solution.

7 0
4 years ago
A uniform solid sphere has a moment of inertia I about an axis tangent to its surface. What is the moment of inertia of this sph
arsen [322]

Answer:

option E

Explanation:

given,

I is moment of inertia about an axis tangent to its surface.

moment of inertia about the center of mass

I_{CM} = \dfrac{2}{5}mR^2.....(1)

now, moment of inertia about tangent

I= \dfrac{2}{5}mR^2 + mR^2

I= \dfrac{7}{5}mR^2...........(2)

dividing equation (1)/(2)

\dfrac{I_{CM}}{I}= \dfrac{\dfrac{2}{5}mR^2}{\dfrac{7}{5}mR^2}

\dfrac{I_{CM}}{I}=\dfrac{2}{7}

I_{CM}=\dfrac{2}{7}I

the correct answer is option E

4 0
3 years ago
You are standing 10 meters from a light source. Then, you back away from the light source until you are 20 meters away from it.
aliya0001 [1]
From my new perspective, the new intensity of the
light source has decreased by a factor of four.
7 0
3 years ago
Read 2 more answers
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