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mash [69]
3 years ago
12

Suppose an object in freefall is dropped from a building it’s starting velocity is 0m/s. Ignoring the facts of air resistance wh

at is the speed (in m/s) of the object after falling three seconds?
Physics
1 answer:
Alja [10]3 years ago
3 0

v = v₀ + at

v = final speed, v₀ = initial speed, a = acceleration, t = elapsed time

Given values:

v₀ = 0m/s (starts from rest), a = 9.81m/s², t = 3s

Plug in and solve for v:

v = 0 + 9.81(3)

v = 29.4m/s

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Element or a compound.

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Which statement is true about a falling object? (Assume no
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Which of the following is a good example of a physical change?
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3 years ago
A thermally isolated system consists of a hot piece of aluminum and a cold piece of copper. The aluminum and the copper are in t
RoseWind [281]

Answer:

Explanation:

Make up a question.

The only change is going to be c.

Suppose they aluminum starts our higher at 50oC

Suppose the copper starts out at 20oC

Suppose the mass of both are 25 grams.

Aluminum

m*2c * deltat

  • deltat = 50 - x
  • c = 2*c
  • m = 25

Copper

m*c*deltat

deltat = x - 20

m = 25

c = c

Now since the amount of heat is the same (this starts out on a heated slab of something).

m*2c * (50 - x) = m * c * x - 20  The m and the c are the same. Cancel them out.

2 * (50 - x) = (x - 20)    Remove the brackets.

100 - 2x = x - 20          Add 20 to both sides.

120 - 2x = x                  Add 2x to both sides.

120 = 3x                       Divide by 3

x = 40

What does this tell you?

It tells you that the temperature of the aluminum is only going to drop 10 degrees

The copper is going to gain 40 - 20 = 20  degrees.

The heat transfer is actually the same. It doesn't take as much heat to heat copper as it does aluminum. That's shown by the difference in how the temperature changes. One looses 10 degrees. The other gains 20. The transfer is the same because of the way the "c" operates.        

5 0
2 years ago
Please explain how you got the answer :(
tensa zangetsu [6.8K]

Answer:

36.5 kJ

Explanation:

Energy by machine = energy to machine × efficiency

E = 52.1 kJ × 0.70

E = 36.5 kJ

3 0
3 years ago
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