Answer:
f=-1380N
Explanation:
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds
.the concluding part to the question should be
What is the impact force (impulse) on the board?
solution
from the Newton's second law of motion which states that
the rate of change in momentum is directly proportional to the force applied
f=m(v-u)/t
f=0.3(0-23.3)/0.005
f=-1380N
f=force impact
m=mass of the karates master's hand
t=time for the impact
v=0m/s final velocity
u=initial velocity
The moment of inertia of when it is rotated around the -axis .
Solution:
=
=
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Consider a line that passes through the center of the ring and is perpendicular to the plane of the ring. Let R be the radius of the ring and M be its mass. All elements are at the same distance from the axis of rotation. The moment of inertia formula is the sum of the mass products of each particle multiplied by the square of the distance from the axis of rotation.
Moments of inertia oppose the rotational motion, so they are called moments of inertia rather than moments of force. A moment of inertia is defined with respect to a particular axis of rotation. The moment of inertia of a mass with respect to an axis is defined as the square of the mass times the distance from the axis.
Learn more about The axis here:- brainly.com/question/21191648
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Answer:
240.59 N
Explanation:
We are given that
Mass per unit length=m/l=
Fundamental frequency,f=146.8 Hz
Tension=T=82.4 N
Mass per unit length=
We have to find the tension.
Velocity,v=
New tension,T'=
Hence, the string should have tension 240.59 N so that its fundamental frequency is 146.8 Hz
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.
Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)
The unit for velocity (to be used here) is m/s or ms⁻¹
B. The sound of the engine will get louder and the pitch higher.