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Olegator [25]
3 years ago
10

lana picked a pumpkin that weighed three times the weight of meg's pumpkin megs pumpkin wqs half the weight of ryans pumpkin. Ry

ans pumpkin weighed 14 pounds. How much did lana's pumpkin weigh ?
Mathematics
2 answers:
kolbaska11 [484]3 years ago
7 0
Hey!

STEP 1:

14/2 = 7

STEP 2:

14 × 3 = 21

So, Lana's pumpkin weighed 21 pounds.
liraira [26]3 years ago
4 0
14 ÷ 1/2 × 3 (I hope it's right. I would have done this)
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Answer this question please and I will give brainliest
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Answer:

Jordan

Step-by-step explanation:

Because each person is in debt the one with the least amount of dept will pay less. Think of it like this:

You owe the bank 85 dollars so your account balance is -85 since you owe money

if you were to owe 100 dollars then you owe more money.

Therefore owing 85 dollars is the least amount of money owed in this case

8 0
2 years ago
11 identical pairs of Air Jordan cost $660.What is the cost of one pair?
Crank

Answer:

$60

Step-by-step explanation:

11 identical pairs of Air Jordan cost $660.

To find the cost of one pair, you have simply to divide the total amount paid by the total number of pairs.

Total amount paid = $660

Total number of pairs = 11

The cost of one pair =\$660 : 11=\$60

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3 years ago
The figures are similar. Find x.
DaniilM [7]

Answer:

My own answer to your question is x=10

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2 years ago
Please help me !!! I will give you brainliest !!!!
MatroZZZ [7]

Sorry if it's wrong, I tried

6 0
2 years ago
Read 2 more answers
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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