the emission of electrons or other free carriers when light shines on a material.
Answer:
The specific heat capacity can be defined as the amount of heat required to raise the temperature of 1 unit of mass by 1 unit temperature. The specific heat capacity of water is 4.186 joule/gram °C which is higher than common substances. The land has lower specific heat capacity. Thus, the land gets hot quickly than water.
This results in warming up air near the land which creates a difference in pressure across the coastal region. Sea breeze blows from sea towards landmass. Opposite happens at night, when water is still warm and land gets cooled down quickly. Then land breeze blows from landmass towards the sea. This breeze maintains a moderate temperature and windy and humid weather in the coastal regions.
If you cannot get a chair to move across the floor, it is because static friction opposes your push. When you say static or kinetic friction the two object that facing each other are opposing each other. That's why you're having a hard time pushing the chair.
Answer:
The magnitude of the flux of electric field through a square of surface area is zero.
Explanation:
![E=100 NC^{-1}\\\\A=2 m^2\\\\Electic\,\,flux\,\,flux\,\,is\,\,given\,\,as:\\\\\phi_E=E.A\,cos\,\theta](https://tex.z-dn.net/?f=E%3D100%20NC%5E%7B-1%7D%5C%5C%5C%5CA%3D2%20m%5E2%5C%5C%5C%5CElectic%5C%2C%5C%2Cflux%5C%2C%5C%2Cflux%5C%2C%5C%2Cis%5C%2C%5C%2Cgiven%5C%2C%5C%2Cas%3A%5C%5C%5C%5C%5Cphi_E%3DE.A%5C%2Ccos%5C%2C%5Ctheta)
It is given that square box is parallel to yz-plane which has normal vector perpendicular to plane in x-direction. Angle between normal vector of area and electric field is 90°. Substituting in (1)
![\phi_E=E.A\,cos\,(90^o)\\\\\phi_E=0](https://tex.z-dn.net/?f=%5Cphi_E%3DE.A%5C%2Ccos%5C%2C%2890%5Eo%29%5C%5C%5C%5C%5Cphi_E%3D0)
Answer:
The speed of the electron is
.
Explanation:
Given that,
The magnitude of electric field, ![E=1.32\ kV/m=1.32\times 10^3\ V/m](https://tex.z-dn.net/?f=E%3D1.32%5C%20kV%2Fm%3D1.32%5Ctimes%2010%5E3%5C%20V%2Fm)
The magnitude of magnetic field, B = 0.516 T
Both the magnetic and electric fields are acting on the moving electron. Then, the magnitude of electric field and magnetic field is balanced such that :
![evB=eE\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.32\times 10^3}{0.516}\\\\v=2558.13\ m/s](https://tex.z-dn.net/?f=evB%3DeE%5C%5C%5C%5Cv%3D%5Cdfrac%7BE%7D%7BB%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B1.32%5Ctimes%2010%5E3%7D%7B0.516%7D%5C%5C%5C%5Cv%3D2558.13%5C%20m%2Fs)
or
![v=2.55\times 10^3\ m/s](https://tex.z-dn.net/?f=v%3D2.55%5Ctimes%2010%5E3%5C%20m%2Fs)
So, the speed of the electron is
. Hence, this is the required solution.