Answer:
The angular separation equals 
Explanation:
We have according to Snell's law


Using this equation for both the colors separately we have

Similarly for violet light we have

Thus the angular separation becomes

Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
Because of the pole and the generator you would have to biuld
Answer:
if you look it up i think u can find it it could be a mealltiod Co 27
Explanation:
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