<h2>mass = 25kg</h2><h2>---------------------------------</h2>
force = 75N --- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>
acceleration = 3m/s² ---- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>
<h3>FORCE = mass × acceleration</h3>
75N = mass × 3m/s²
mass = 75÷3
<h3>mass = 25kg</h3><h2>-----------------------------</h2><h2>FOLLOW ME</h2>
Answer:
A) 1.53s
B) 19.8m
C) 2.869m
Explanation:
A) The time of flight for a projectile can be calculated using the formula:
t = 2μsinθ/g
Where; u = velocity
θ = angle
g = acceleration due to gravity (9.8m/s^2)
t = 2 × 15 × sin 30°/9.8
t = 30sin30°/9.8
t = 30 × 0.5/9.8
t = 15/9.8
t = 1.53s
B) The horizontal range (distance) for a projectile can be calculated using the formula:
Range = u²sin2θ/ g
Range = 15² sin 2 × 30 / 9.8
Range = 225 sin 60/9.8
Range = 225 × 0.8660/9.8
Range = 194.855/9.8
Range = 19.8m
C) The maximum height for a projectile can be calculated using the formula:
h = u²sin²θ/2g
h = 15² (sin 30)² / 2 × 9.8
h = 225 × 0.25 / 19.6
h = 56.25/19.6
h = 2.869m
As galáxias são geralmente maiores do que os aglomerados de estrelas. Como disse Geller ~ As galáxias são como as cidades em que vivem os aglomerados de estrelas. As galáxias podem ter cerca de milhares ou mais aglomerados de estrelas ~
I hope it helps ~
We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is
From the Question we are told that
Maximum height 
Minimum height 
Time for next high tide will occur
Generally Average Height
Therefore determine Amplitude to be
Generally, the equation for Time is mathematically given by
At t=0
Where
Therefore
Hence the Time at 
is
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