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Maurinko [17]
3 years ago
12

What provides the centripetal force needed to keep Earth in orbit?

Physics
2 answers:
anyanavicka [17]3 years ago
8 0
The centripetal force is the gravitational attraction
between the Earth and the Sun.
kkurt [141]3 years ago
3 0
The centripetal force needed to keep earth in orbit is gravity.
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Match the following items.
Ray Of Light [21]

Answer:

Je ne Sachez que Qu’est-ce que le

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3 years ago
If you travel from Yakima to Ellensburg (Yakima to Ellensburg is 50 miles) with a speed of 60 miles/hour for half of the
koban [17]

Answer:

\displaystyle \frac{480}{7}\approx 68.6\; \rm mph.

Explanation:

The average speed of an object is equal to total distance over total time.

  • Distance traveled: \rm 50 \; mi.

How much time is taken? This trip is divided into two halves, each of distance \displaystyle \frac{50}{2} = 25\;\rm mi.

Time spent on the first half of the trip:

\displaystyle t_1 = \frac{s_1}{v_1} = \frac{25}{60} = \frac{5}{12}\; \rm hours.

Similarly, time spent on the second half of the trip:

\displaystyle t_2 = \frac{s_2}{v_2} = \frac{25}{80} = \frac{5}{16}\; \rm hours.

In total:

\displaystyle \frac{5}{12} + \frac{5}{16} = \frac{35}{48} \; \rm hours.

Average speed:

\begin{aligned} \text{Average speed} &= \frac{\text{Total Distance}}{\text{Total Time}}\\ &= 50 \left/\frac{35}{48}\right.\\ &= 50 \cdot \frac{48}{35} \\&= \frac{480}{7}\approx 68.6\; \rm mph \end{aligned}.

This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to \rm 60\; mph rather than \rm 80\; mph.

3 0
3 years ago
A 5kg book rests on a table. How much force is it exerting on the table?​
valentinak56 [21]

Answer:

5 Kg of Force

Explanation:

3 0
3 years ago
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What is a characteristic of a step down transformer
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Answer:

converts high-voltage, low-current power into low-voltage, high-current power.

Explanation:

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3 years ago
A train moves from rest to a speed of 25 m/s in 30.0 seconds . What is the acceleration
stich3 [128]
When a car moves from rest then the initial velocity,
u = 0m {s}^{ - 1}

The final velocity,

v = 25m {s}^{ - 1}
and time,
t = 30s
Using the equation,
v = u + at
We have,

25 = 0 + a(30)
25 = 30a
\frac{25}{30}  = a
\therefore \: a =  \frac{5}{6} m {s}^{ - 2}
7 0
3 years ago
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