Answer
given,
initial speed of merry-go-round = 0 rad/s
final speed of merry-go-round = 1.5 rad/s
time = 7 s
Radius of the disk = 6 m
Mass of the merry-go-round = 25000 Kg
Moment of inertia of the disk
I = 450000 kg.m²
angular acceleration
we know,
What happens when you decrease the thrust on your scooter? A. You stop B. Nothing happens C. You fall over D. You speed up Reset
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Answer:
the work done by gravity on the boy is 604.62 J
Explanation:
Given;
distance the boy slides, d = 3 m
angle of inclination of the playground, θ = 40⁰
mass of the boy, m = 32 kg
The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.
The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.
The work done by gravity on the boy is calculated as;
W = P.E = mgh
= 32kg x 9.8m/s² x 1.928m
= 604.62 J
Therefore, the work done by gravity on the boy is 604.62 J