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inysia [295]
3 years ago
10

Suppose that a weight on a spring has initial position​ s(0) and period P. ​ s(0)= 1in ;p=0.8

Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0
The question is to find a s function given by s(t) = a cos(ωt) that models the displacement of the weight.

Answer:
The function is given as:
s(t) = a cos(ωt)
This means that to get the exact function modelling the given situation, we will have to get values for ω and a.

1- getting the value of ω:
period = 0.8 sec
frequency = 1/period = 1/0.8 = 5/4 hz
ω = 2πf = 2*π*5/4 = 2.5π rad/sec
The function now became:
s(t) = a cos(2.5πt)

2- getting the value of a:
We are given that:
s(0) = 1 in
This means that:
s(t) = a cos(2.5πt)
1 = a cos(2.5π*0)
1 = a cos(0)
a = 1

Therefore, the function is:
s(t) = cos(2.5πt)

To get the value of the function at any instance (t), substitute with the value of "t" in the above function and get the corresponding s(t)

Hope this helps :)

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For which value of x is the equation 3x + x = 2x + 24 true?
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Answer:

D) 12

Step-by-step explanation:

3x+x=2x+24

4x=2x+24

4x-2x=24

2x=24

x=24/2

x=12

4 0
3 years ago
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photoshop1234 [79]

Answer:

Given expression is equal to  1/32

Step-by-step explanation:

Given that:

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To eliminate "-" sign we will invert the fraction as follows:

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Or it can be written as:

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This is the simplified expression.

i hope it will help you!

8 0
3 years ago
Stanley noticed that he is both the 10th tallest and the 10th shortest student in his class. If everyone in the class is at a di
STALIN [3.7K]

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The length of the diagonal of a rectangle is 181 inches.
egoroff_w [7]

Answer:

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Step-by-step explanation:

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Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
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