Complete Question:
Two 3.0µC charges lie on the x-axis, one at the origin and the other at 2.0m. A third point is located at 6.0m. What is the potential at this third point relative to infinity? (The value of k is 9.0*10^9 N.m^2/C^2)
Answer:
The potential due to these charges is 11250 V
Explanation:
Potential V is given as;
where;
K is coulomb's constant = 9x10⁹ N.m²/C²
r is the distance of the charge
q is the magnitude of the charge
The first charge located at the origin, is 6.0 m from the third charge; the potential at this point is:
The second charge located at 2.0 m, is 4.0 m from the third charge; the potential at this point is:
Total potential due to this charges = 4500 V + 6750 V = 11250 V
Explanation:
We have,
Mass of a box is 115 kg
Applied force is 424 N
It is required to find the frictional force of the floor on the box against you. Frictional force is an opposing force. It opposes the motion of an object. Here the applied force is 424 N. So, the frictional force has a magnitude of 424 N but it acts in opposite direction.
We are asked in this problem to determine the power wasted given the two voltages: 50,000 and 12,000 volts. By physics, the formula to determine power using volts is expressed as P = VI where P is in watts, V is in volts and I, current, is in Amperes. In this case, we just have to plug the given data to the equation named.
1) P1 = 50,000*I
2) P2 = 12,000 * I
P1 - P2 = (50,000-12,000)*I
ΔP = 48,000 I
So the power wasted then is equal to 48,000 times the current employed to achieve power. I should be specified as well to determine the exact difference.
I would say that you may check in ..........g....o...o...g....l....e
B) <span>Beaker, funnel, filter paper, stirring rod, iron ring, and stand</span>
