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8_murik_8 [283]
4 years ago
6

Why do the giant planets and their moons have compositions different from those of the terrestrial planets?

Physics
1 answer:
dangina [55]4 years ago
4 0

Answer and Explanation:

The formation of planets ,initially was the result of gradual accumulation of  solid matter into the solar nebula. As a result of high temperature in the interior of our solar system, metals and rocks were the only materials to get compressed.

The matter that was volatile could not be compressed so close to the heat energy radiated by the early Sun.

On the outer part of the solar system, solid matter included hydrogen compounds, rocks and metals  with a lot of matter for planet formation.

The Giant planets were formed by capturing Helium and hydrogen gases as well whereas the terrestrial planets being much more smaller are made up of mainly rocks like silicates and metals like iron.

The moons of terrestrial planets like that of Earth is also terrestrial in nature consisting of rocks and metals as the constituent material while that of giant planets consist of frozen water in half the proportion and the other half is rocks and metals.

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Answer:

Approximately 4.2\; {\rm s} (assuming that the projectile was launched at angle of 35^{\circ} above the horizon.)

Explanation:

Initial vertical component of velocity:

\begin{aligned}v_{y} &= v\, \sin(35^{\circ}) \\ &= (36\; {\rm m\cdot s^{-1}})\, (\sin(35^{\circ})) \\ &\approx 20.6\; {\rm m\cdot s^{-1}}\end{aligned}.

The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing y_{1} is the same as the altitude y_{0} at which this projectile was launched: y_{0} = y_{1}.

Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 20.6\; {\rm m\cdot s^{-1}} (upwards,) the vertical velocity right before landing would be (-20.6\; {\rm m\cdot s^{-1}}) (downwards.) The change in vertical velocity is:

\begin{aligned}\Delta v_{y} &= (-20.6\; {\rm m\cdot s^{-1}}) - (20.6\; {\rm m\cdot s^{-1}}) \\ &= -41.2\; {\rm m\cdot s^{-1}}\end{aligned}.

Since there is no drag on this projectile, the vertical acceleration of this projectile would be g. In other words, a = g = -9.81\; {\rm m\cdot s^{-2}}.

Hence, the time it takes to achieve a (vertical) velocity change of \Delta v_{y} would be:

\begin{aligned} t &= \frac{\Delta v_{y}}{a_{y}} \\ &= \frac{-41.2\; {\rm m\cdot s^{-1}}}{-9.81\; {\rm m\cdot s^{-2}}} \\ &\approx 4.2\; {\rm s} \end{aligned}.

Hence, this projectile would be in the air for approximately 4.2\; {\rm s}.

8 0
2 years ago
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What are the 4 forces that are at work within the nucleus of an atom
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<span>Electromagnetic, Strong Nuclear, Weak Nuclear, and Gravity</span>
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The data table depicts an object moving with changing speed.<br><br> True<br> False
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3 years ago
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You slide down a steep slide at an amusement park. The slide is set up so that you are sitting on a blanket so that only the bla
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Answer:

a. Your acceleration decreases, but never goes to zero.

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Pushing down with hands on the blanket increases the normal force between the soil and the blanket and, therefore, increases the friction force. Nonetheless, the component of the gravity force parallel to the direction of the slide is higher than friction force and consequently, the acceleration decreases but never goes to zero.

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At a construction site a pipe wrench struck the ground with a speed of 31 m/s. (a) From what height was it inadvertently dropped
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Answer:

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