Answer:
a) Δφ = 1.51 rad
, b) x = 21.17 m
Explanation:
This is an interference problem, as they indicate that the distance AP is on the x-axis the antennas must be on the y-axis, the phase difference is
Δr /λ = Δfi / 2π
Δfi = Δr /λ 2π
Δr = r₂-r₁
let's look the distances
r₁ = 57.0 m
We use Pythagoras' theorem for the other distance
r₂ = √ (x² + y²)
r₂ = √(57² + 9.3²)
r₂ = 57.75 m
The difference is
Δr = 57.75 - 57.0
Δr = 0.75 m
Let's look for the wavelength
c = λ f
λ = c / f
λ = 3 10⁸ / 96.0 10⁶
λ = 3.12 m
Let's calculate
Δφ = 0.75 / 3.12 2π
Δφ = 1.51 rad
b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains
Δr = (2n + 1) λ / 2
For the first interference n = 0
Δr = λ / 2
Δr = r₂ - r₁
We substitute the values
√ (x² + y²) - x = 3.12 / 2
Let's solve for distance x
√ (x² + y²) = 1.56 + x
x² + y² = (1.56 + x)²
x² + y² = 1.56² + 2 1.56 x + x²
y2 = 20.4336 +3.12 x
x = (y² -20.4336) /3.12
x = (9.3² -20.4336) /3.12
x = 21.17 m
This is the distance for the first minimum
Answer:
See the explanation below.
Explanation:
The units of work are consistent since if we work in the international system of measures we have the following dimensional quantities for velocity, distance and time.
s = displacement [m]
v and u = velocity [m/s]
t = time [s]
Now using these units in the given equation.
![s = 0.5*([m/s]+[m/s])*[s]\\s=0.5*[m/s]*[s]\\s = 0.5*[m]](https://tex.z-dn.net/?f=s%20%3D%200.5%2A%28%5Bm%2Fs%5D%2B%5Bm%2Fs%5D%29%2A%5Bs%5D%5C%5Cs%3D0.5%2A%5Bm%2Fs%5D%2A%5Bs%5D%5C%5Cs%20%3D%200.5%2A%5Bm%5D)
So the expression is good, and dimensional has consistency.
Answer:
(d) ATP molecules are produced in the cytosol as glucose is converted into pyruvate.
Answer:
Energy loss per minute will be 
Explanation:
We have given the star produces power of 
We know that 1 W = 1 J/sec
So 
Given time = 1 minute = 60 sec
So the energy loss per minute 
We multiply with 60 we have to calculate energy loss per minute
Your answer is false since science is a subject not a religion