10. A kicked soccer ball has an initial velocity of 30 m/s at an angle of 42° above the horizontal, level
1 answer:
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Answer:
Third displacement = 2.81 m which is 61.70° north of east.
Explanation:
Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
She sails 2 km east, displacement = 2 i
Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis
Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j
Let third displacement be x i + y j
We have final displacement = 5.80 km east = 5.80 i
From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j
= (4.47+x) i + (y - 2.47) j
Comparing both , we have 4.47+x = 5.80
x = 1.33
y-2.47=0
y = 2.47 j
So third displacement = 1.33 i + 2.47 j
Magnitude of third displacement =
θ = tan⁻¹(2.47/1.33) = 61.70°
So third displacement = 2.81 m which is 61.70° north of east.
Answer:
The time taken by the student to climb is 12.25 seconds and work done is 2450 J.
Explanation:
Given that,
Mass of the student, m = 50 kg
The student climbs to a height of 5 meters at a constant speed.
The student's power output is 200.0 W, P = 200 W
The power of an object is given by work done divided by time taken. So,
(b) W is work done,
(b)
So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.
Answer:
The correct answer will be:
(a) 27.3 m/s
(b) 3.8 s
Explanation:
According to the question:
Acceleration,
Time,
(a)
The gazelles top speed will be:
⇒
or,
(b)
As we know,
s = 30 m
Now,
⇒
or,
⇒
On putting the given values, we get
or,