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suter [353]
3 years ago
11

10. A kicked soccer ball has an initial velocity of 30 m/s at an angle of 42° above the horizontal, level

Physics
1 answer:
Serhud [2]3 years ago
5 0

Answer:

ZAMN

Explanation:

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Pascal's Principle states that (a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished
nika2105 [10]

Answer:

a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished at every point in the fluid and on the walls of the container.

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area(A2) of the piston.

P=F/A

P1=P2

F1/ A1= F2/ A2

F2= F1* A2/ A1

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

In an incompressible liquid, the volume and amount of mass does not vary when pressure is applied.

5 0
3 years ago
Why is work measured in
erastova [34]

Answer:

C) the equation consists of two factors:

work = force * distance

W = F · S

8 0
2 years ago
URGENT What does Newton's third law say about why momentum is conserved in collisions?
valentinak56 [21]
Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.For such a collision<span>, the forces acting between the two objects are equal in magnitude and opposite in direction</span>
4 0
3 years ago
Read 2 more answers
All of these are very important parts of studying physics EXCEPT
Sergeeva-Olga [200]

Answer:

4. deducing and applying natural laws

5 0
3 years ago
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A bullet of mass 20g is horizontally fired with a velocity of 150m/s from a pistol of mass 2 kg. What is the
kiruha [24]

Answer:

m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (u1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

Total momentum of the pistol and bullet after it is fired is

= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

3 + 2v = 0

→v = -1.5 m/s  

7 0
3 years ago
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