Missing question (found on internet):
"what is the force of the car?"
Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
For the car in the problem,
So the force that accelerates the car is
Answer:
- Here we use the conservation of momentum theorem.
- m stands for mass, and v stands for velocity. The numbers refer to the respective objects.
- m1v1 + m2v2 = m1vf1 + m2vf2
- Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.
- m1v1 + m2v2 = vf(m1 + m2)
<u>Let’s substitute in our givens.</u>
(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)
I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.
Note that I have considered the bullet’s velocity to be in the positive direction,
The answer is vf = 0.280 m/s
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Answer:
a ball hanging from a tall pole
Explanation:
work is force times a distance in the direction of the force. The ball just hanging there has no motion, so is associated with no work. Work was probably done in the hanging process, but none after.
Answer:
C. the bottom
Explanation:
The tires of the car is rolling without slipping. In this case, the bottom of the tire that contacts the surface must be at rest in order to prevent slipping. Of course this is instantaneously. The tire has a translational velocity, v, and also at the bottom a rotational velocity, -v, and the sum is zero for the bottom.
