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aleksklad [387]
2 years ago
10

What is the Equation of Reduction in Mg+F2 gives MgF2, I WILL MARK YOU AS BRAINLIST

Chemistry
1 answer:
skad [1K]2 years ago
5 0

Answer:

Mg+F2= Mgf2

Explanation:

F 2 is an oxidizing agent, Mg is a reducing agent. ; Pale-yellow to greenish gas with a pungent, irritating odor.

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Law of Lateral Continuity The Grand Canyon.

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he same rock layers on opposite sides of the canyon. The matching rock layers were deposited at the same time, so they are the same age.

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3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit. 
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8 0
3 years ago
What is gamma rays burst​
storchak [24]

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In gamma-ray astronomy, gamma-ray bursts are immensely energetic explosions that have been observed in distant galaxies. They are the brightest and most energetic electromagnetic events known to occur in the universe. Bursts can last from ten milliseconds to several hours. b

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6 0
3 years ago
Read 2 more answers
Evaluate each scenario to determine whether it represents a chemical reaction.
vova2212 [387]

Explanation:

A chemical reaction is one in which a chemical change occurs.

During a chemical change;

  • The process is irreversible
  • New kinds of matter produced
  • There is a change in mass

Based on these premise;

 Baking  cake batter is a chemical reaction because you cannot reverse the process

  Shredding a paper is not a chemical reaction because no new kind of matter is produced.

  Twisting of a metal wire is not a chemical reaction

   Yellowing of newspaper in sunlight is a chemical change. The process cannot be reversed

8 0
2 years ago
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An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
natima [27]

Answer:

The answer is "Option B".

Explanation:

\to CH_3COOH + NaOH \longleftrightarrow  CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\  NaOH = (5 \ E-3\  L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\

\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\  L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\

\to C \ CH_3COONa =  \frac{(0.01\  mol + 5 \ E-4\  mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\

\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\  E-6 - 1.75\  E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to  [H_3O^+] = 1.5835\  E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to  pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7

5 0
3 years ago
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