Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.
Explanation:
density
ρ
=
Mass
Volume
, and thus units of
g
⋅
m
L
−
1
are reasonable.
For this problem:
17.4
⋅
m
L
×
0.798
⋅
g
⋅
m
L
−
1
≅
14
⋅
g
but A i supposed?
More than one atom
- Hope this helps :)
Answer:
PbSO4 is not a covalent compound.
Explanation:
PbSO4 is an ionic compound.
Answer:
16.5 days
Explanation:
Given that:
Half life = 26.5 days
Where, k is rate constant
So,
The rate constant, k = 0.02616 days⁻¹
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given:
35.0 % is decomposed which means that 0.35 of is decomposed. So,
![\frac {[A_t]}{[A_0]}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D)
= 1 - 0.35 = 0.65
t = 7.8 min
![\frac {[A_t]}{[A_0]}=e^{-k\times t}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-k%5Ctimes%20t%7D)
<u>t = 16.5 days.</u>
Answer:
0.1 mol×L
Explanation:
Concentration= MOLES of SOLUTE / Volume of SOLUTION
So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml
So, MOLES of SOLUTE
x 100 x 10-L = ??mol; this was our starting solution.
And final CONCENTRATION=
0.15 . mol. 5 x 100 x 10-3L/
= 0.15 mol · L-1 150 x 10 3
=0.1 mol · L
