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Fantom [35]
3 years ago
5

What is the total number of moles of hydrogen gas contained in 9.03 x 10^23 molecules

Chemistry
2 answers:
Mrac [35]3 years ago
5 0
Answer is 1.2 x 1024 atoms. Explanation: Divide 9.03 x 1023 by 6.02 x 1023 to find the number of moles of hydrogen gas. 9.02 / 6.02 = 1.5 moles (remember the numerator and denominator each contain 10 to the 23, so this cancels out. 1 mole equals 6.02 x 1023 molecules).
Lilit [14]3 years ago
3 0

Answer:

The answer is 1,5 moles of H2

Explanation:

Let's start from the definition of the Avogadro's number. The Avogadro's number is 6,02 x 10^{23} and means that, for any compound, we have 6,02 x 10^{23} molecules for each mol. So, in that way, we can write the following expression:

9,03*10^{23} molecules H2* \frac{1 mol H2}{6,02 * 10^{23} molecules H2}

The result is: 1,5 moles of H2

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A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
Andreas93 [3]
<h3>Answer:</h3>

2.809 L of H₂SO₄

<h3>Explanation:</h3>

Concept tested: Moles and Molarity

In this case we are give;

Mass of solid sodium hydroxide as 13.20 g

Molarity of H₂SO₄ as 0.235 M

We are required to determine the volume of H₂SO₄ required

<h3>First: We need to write the balanced equation for the reaction.</h3>
  • The reaction between NaOH and H₂SO₄ is a neutralization reaction.
  • The balanced equation for the reaction is;

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

<h3>Second: We calculate the umber of moles of NaOH used </h3>
  • Number of moles = Mass ÷ Molar mass
  • Molar mass of NaOH is 40.0 g/mol
  • Therefore;

Moles of NaOH = 13.20 g ÷ 40.0 g/mol

                          = 0.33 moles

<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>
  • From the equation, 2 moles of NaOH reacts with 1 mole of H₂SO₄
  • Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
  • Thus, Moles of H₂SO₄ = moles of NaOH × 2

                                    = 0.33 moles × 2

                                   = 0.66 moles of H₂SO₄

<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>
  • When given the molarity of an acid and the number of moles we can calculate the volume of the acid.
  • That is; Volume = Number of moles ÷ Molarity

In this case;

Volume of the acid = 0.66 moles ÷ 0.235 M

                                = 2.809 L

Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.

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