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Fantom [35]
3 years ago
5

What is the total number of moles of hydrogen gas contained in 9.03 x 10^23 molecules

Chemistry
2 answers:
Mrac [35]3 years ago
5 0
Answer is 1.2 x 1024 atoms. Explanation: Divide 9.03 x 1023 by 6.02 x 1023 to find the number of moles of hydrogen gas. 9.02 / 6.02 = 1.5 moles (remember the numerator and denominator each contain 10 to the 23, so this cancels out. 1 mole equals 6.02 x 1023 molecules).
Lilit [14]3 years ago
3 0

Answer:

The answer is 1,5 moles of H2

Explanation:

Let's start from the definition of the Avogadro's number. The Avogadro's number is 6,02 x 10^{23} and means that, for any compound, we have 6,02 x 10^{23} molecules for each mol. So, in that way, we can write the following expression:

9,03*10^{23} molecules H2* \frac{1 mol H2}{6,02 * 10^{23} molecules H2}

The result is: 1,5 moles of H2

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Witch two conditions can limit the usefulness of the kinetic molecular theory in describing gas behavior?
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Which two conditions can limit the usefulness of the kinetic-molecular theory in describing gas behavior? ... Increasing pressure is causing a smaller change in gas volume. The closeness of particles of gas and their low speeds allow intermolecular forces to become important at certain pressured and temperature.

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4 years ago
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A uranium atom has 92 protons in it nucleus use what you know about atoms to predict how many electrons a neutral uranium atom h
sladkih [1.3K]
A neutral atom is one that has no net charge. In other words, the number of positive charges cancels out with the number of negative charges, so the number of protons equals the number of electrons. Uranium has 92 protons, which means it has a total positive charge of +92. To have a neutral charge, the atom MUST have 92 electrons, as that is a negative charge of -92, and the net charge is ultimately (protons + electrons) = ([+92] + [-92]) = 0. 
6 0
3 years ago
A compound is 53. 31% c, 11. 18% h, and 35. 51% o by mass. What is its empirical formula? insert subscripts as needed.
lyudmila [28]

Answer:

C2H5O

Explanation:

In a 100 g sample we would have

53.31 g of C

11.18g of H

35.51g of O

First, we find the relative number of atoms of each element by dividing the number of grams the element has in the compound by its atomic mass.

Atomic mass of carbon is 12.011

Relative number of carbon atoms = 53.31 / 12.011 = 4.4

Atomic mass of hydrogen = 1.007

Relative number of hydrogen atoms : 11.18/1.007 = 11.1

Atomic mass of oxygen : 15.999

Relative number of oxygen atoms : 35.51 / 15.999 = 2.2


Now we find a ratio of the relative number of atoms by dividing the # of relative atoms of each element by the element's relative number of atoms that had the lowest number. ( oxygen which had 2.2 ) The outcome of each will be the subscript or number of atoms of each element.

Carbon : 4.4 / 2.2 = 2

Hydrogen : 11.1 / 2.2 = 5

Oxygen : 2.2 / 2.2 = 1

The answer is C2H5O

8 0
2 years ago
I need help question 7
algol [13]

Answer:

B

Explanation:

As you can see in these 4 examples, B- looks completely different from A, C, D! In B: The reactants and products are completely different in the Element Figures.

8 0
3 years ago
Lead (Pb) is used to make a number of different alloys. What is the mass of lead present in an alloy containing 0.15 mol of lead
Vesna [10]
Lead is 207.2 g/mol.
0.15 mol (\frac{207.2g}{mol}) = 31.08 g Pb
3 0
3 years ago
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