Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms<span> of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.</span>
do you mean fractional distillation of crude oil ?
if you do then this is what happens:
basically, crude oil is made up of a lot of hydrocarbons so it's put into a fracitonating column to separate these compounds into fractions. the top of the fractionating column is colder whereas the bottom of the column is hotter.
gases, petrol, diesel and kerosene come out near the top of the top of the column because they are shorter chains. substances near the top of the column also have a lower boiling point (since it's cooler and there's less intermolecular forces).
the substances at the top of the column are typically useful fuels because they have a higher ease of ignition (higher up=easier to ignite, lower down = harder to ignite). Also, substances at the top have a low viscosity so they can flow easily.
substances that come out near the bottom of the fracitonating column include fuel oil and bitumen.
these are longer chains of hydrocarbons and bitumen is used for road surfacing.
these substances have a high viscosity (harder to flow) and have a high boiling point since they have more intermolecular forces which require a lot of energy to break. Also the bottom of the fractionating column is warmer and this is where these fractions are released.
Answer:
The concentration of the diluted solution is 3.75 M
Explanation:
Step 1: Data given
Volume of a stock solution = 75 mL = 0.075 L
The molarity of stock solution = 5.0 M
We add 25 mL, The total volume is 100 mL = 0.100 L
Step 2: Calculate the concentration of the diluted solution
C1*V1 = C2*V2
⇒with C1 = the initial concentration = 5.0 M
⇒with V1 = the initial volume = 0.075 L
⇒with C2 = the new concentration = TO BE DETERMINED
⇒with V2 = the diluted volume = 0.100 L
5.0 M * 0.075 L = C2 * 0.100L
C2 = (5.0M * 0.075 L) / 0.100 L
C2 = 3.75 M
The concentration of the diluted solution is 3.75 M
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