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taurus [48]
3 years ago
8

Please help me i need this asp (will me mark brainless)

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

A balanced chemical reaction equation is one in which the number of atoms of each of the atoms are the same on both sides of the reaction equation.

<h3>Balanced reaction equation</h3>

A balanced reaction equation is a type of reaction equation in which the number of atoms of each reactant on both sides of the reaction equation are the same.

Let us now try to balance each reaction;

  • 2H2 + O2 ----> 2H2O
  • S8 + 12O2 -------> 8SO3
  • 2HgO ----> 2Hg + O2
  • Zn + 2HCl ------> ZnCl2 + H2

Hence a balanced chemical reaction equation is one in which the number of atoms of each of the atoms are the same on both sides of the reaction equation.

Learn more about balancing reaction equations: brainly.com/question/7358082

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Answer:

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4 years ago
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How many of the planets have an orbital period of less than one Earth year?
GrogVix [38]

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8 0
3 years ago
How many molecules of F2 in 90g F2
Bogdan [553]
I dont know good luck!
7 0
3 years ago
If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
Alina [70]

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

3 0
3 years ago
can anyone explain to me how to balance a chemical equation? im having trouble in understanding how i keep getting it wrong.
Virty [35]
For example we are going to use this unbalanced chemical reaction:
H₂ + O₂ → H₂O.
First, calculate number of atoms (hydrogens and oxygens) on left and right. There is two oxygen and two hydrogen on left and two hydrogen and one oxygen on right.
You can not change molecular formula of compound, only you can put coefficient in fron of compound to balance reaction.
Put 2 in front water to balance oxygen (now you have two oxygens on left and right). But now you have four hydrogens on right, so you must put 2 in fron hydrogen on the left.
2H₂ + O₂ → 2H₂O.
6 0
3 years ago
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